Answer:
a) The probability that a box containing 3 defectives will be shipped is
b) The probability that a box containing only 1 defective will be sent back for screening is
Step-by-step explanation:
Hi
a) The first step is to count the number of total possible random sets of taking a sample size of 4 items over 23 items of the box, so
The second step is to count the number of total possible random sets of taking a sample size of 4 items over 20 items of the box (discounting the 3 defectives) as the possible ways to succeed, so
Finally we need to compute , therefore the probability that a box containing 3 defectives will be shipped is
a) The first step is to count the number of total possible random sets of taking a sample size of 4 items over 23 items of the box, so
The second step is to count the number of total possible random sets of taking a sample size of 4 items over 22 items of the box (discounting the defective 1) as the possible ways to succeed, so
Then we need to compute , therefore the probability that a box containing 1 defective will be shipped is
Finally the probability that a box containing only 1 defective will be sent back for screening will be
[2 sin(x) cos(x)] X [Sin(x)/cos(x)]
<span>The cosines cancel out, as one is in the numerator and one is in the denominator. So you are left with:: </span>
<span>2 sin(x) sin(x) </span>
<span>or: </span>
<span>2 sin(x) [squared]
I hope this helps! </span>
The answer is 43 because when you multiply 6x6 you get 36 and if you add 6 more you get 42 which is one less that 43
Answer:
No
Step-by-step explanation:
15/20 is reduced to 3/4. Not equal to 4/5
Answer:
rearing the numbers and that is it