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3 years ago

Which of the following best describes rotational symmetry

Mathematics

1 answer:

Gala2k [10]3 years ago

7 0

Answer: B

Step-by-step explanation:

A best describes the quality of symmetry, not specifically rotational symmetry.

C applies to that of A.

D applies to flipping an image across an axis.

B specifically outlines the symmetry of an object when rotated, thus B would be the most precise answer.

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Taj had 15 books. He gave some of the books to his friends.

deff fn [24]

The answer is B six books, hope this helps!

7 0

3 years ago

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22 POINTS

Harlamova29_29 [7]

Answer:

C. 2, -2, -6

Step-by-step explanation:

18, 14, 10, 6, ?

18 - 4 = 14

14 - 4 = 10

10 - 4 = 6

6 - 4 = 2

2 - 4 = -2

-2 - 4 = -6

They are subtracting each number by 4 to get the next one that continues.

Hope this helped!

Have a supercalifraglisticexpialidocious day!

7 0

2 years ago

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Find the length of the side of a square whose area is 2500 sq. cm PLS FIND ITS ANSWER............................

Sunny_sXe [5.5K]

Answer:

50cm

Step-by-step explanation:

The length of the square is the sway are root of its area.

square root of 2500 Is 50cm

Hope this helps.

Good Luck

4 0

3 years ago

Read 2 more answers

Karissa begins to solve the equation (x – 14) + 11 = x – (x – 4). Her work is correct and is shown below. (x – 14) + 11 = x – (x

sdas [7]

Her work is incorrect because she accidentally changed -14 to -7 in the second step.
Working it out from the top we get
(x-14)+11=x-(x-4)
x-14+11=x-x+4
x-3=0+4
Final answer:
x=7
Hope I helped :)

4 0

3 years ago

Read 2 more answers

Find the product of all real values of r for which 1/2x=r-x/7

Dahasolnce [82]

Answer:

$r = \±\sqrt{14$

$Product = -14$

Step-by-step explanation:

Given

$\frac{1}{2x} = \frac{r - x}{7}$

Required

Find all product of real values that satisfy the equation

$\frac{1}{2x} = \frac{r - x}{7}$

Cross multiply:

$2x(r - x) = 7 * 1$

$2xr - 2x^2 = 7$

Subtract 7 from both sides

$2xr - 2x^2 -7= 7 -7$

$2xr - 2x^2 -7= 0$

Reorder

$- 2x^2+ 2xr -7= 0$

Multiply through by -1

$2x^2 - 2xr +7= 0$

The above represents a quadratic equation and as such could take either of the following conditions.

(1) No real roots:

This possibility does not apply in this case as such, would not be considered.

(2) One real root

This is true if

$b^2 - 4ac = 0$

For a quadratic equation

$ax^2 + bx + c = 0$

By comparison with $2x^2 - 2xr +7= 0$

$a = 2$

$b = -2r$

$c =7$

Substitute these values in $b^2 - 4ac = 0$

$(-2r)^2 - 4 * 2 * 7 = 0$

$4r^2 - 56 = 0$

Add 56 to both sides

$4r^2 - 56 + 56= 0 + 56$

$4r^2 = 56$

Divide through by 4

$r^2 = 14$

Take square roots

$\sqrt{r^2} = \±\sqrt{14$

$r = \±\sqrt{14$

Hence, the possible values of r are:

$\sqrt{14$ or $-\sqrt{14$

and the product is:

$Product = \sqrt{14} * -\sqrt{14}$

$Product = -14$

8 0

3 years ago