X-5/x<4
times both sides by x
x²-5<4x
minus 4x both sides
x²-4x-5<0
factor
(x-5)(x+1)<0
hmm
special points at x=-1 and x=5
when x=-2, we get 10<0 which is false
when x=0, we get -5<0 which is true
when x=6, we get 7<0 which is false
so the solution must be the range between -1 and 5
so if x<0
whaat
just pick the 3rd grah
0.04444444444All you have to do is divide 2/3 by 3/5.
You need to ask your teacher for any help and to evaluate and double check each step.
Answer:
On the left because their both positive and the other one is not and also the left one is on the left y axil
If the circumference is half of the perimeter than the area for both circles would be half of them find one circles area and half it
