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galina1969 [7]
3 years ago
6

What is 5.6 equalivent to

Mathematics
1 answer:
Sloan [31]3 years ago
4 0
(this is for fractions!!!!!!!!!!!!)  28/5 or 5 3/5

i think u just make it into 5.6/1 multiply by 10 which gets 56/10 and wala 
but it's not simplified. 56 and 10 is divisible by 2 so u get 28/5 which is actually 5 3/5 (which is 5.6!!)
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According to industry sources, online banking is expected to take off in the near future. The projected number of households (in
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Answer:

(a) The least-square regression line is: y=4.662+2.709x.

(b) The number of households using online banking at the beginning of 2007 is 31.8.

Step-by-step explanation:

The general form of a least square regression line is:

y=\alpha +\beta x

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<em>x</em> = independent variable

<em>α</em> = intercept

<em>β</em> = slope

(a)

The formula to compute intercept and slope is:

\begin{aligned}        \alpha  &= \frac{\sum{Y} \cdot \sum{X^2} - \sum{X} \cdot \sum{XY} }{n \cdot \sum{X^2} - \left(\sum{X}\right)^2}  \\\beta &= \frac{ n \cdot \sum{XY} - \sum{X} \cdot \sum{Y}}{n \cdot \sum{X^2} - \left(\sum{X}\right)^2}        \end{aligned}

The values of ∑<em>X</em>, ∑<em>Y</em>, ∑<em>XY</em> and ∑<em>X</em>² are computed in the table below.

Compute the value of intercept and slope as follows:

\begin{aligned}        \alpha &= \frac{\sum{Y} \cdot \sum{X^2} - \sum{X} \cdot \sum{XY} }{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} =             \frac{ 68.6 \cdot 55 - 15 \cdot 218.9}{ 6 \cdot 55 - 15^2} \approx 4.662 \\ \\\beta &= \frac{ n \cdot \sum{XY} - \sum{X} \cdot \sum{Y}}{n \cdot \sum{X^2} - \left(\sum{X}\right)^2}        = \frac{ 6 \cdot 218.9 - 15 \cdot 68.6 }{ 6 \cdot 55 - \left( 15 \right)^2} \approx 2.709\end{aligned}

The least-square regression line is:

y=4.662+2.709x

(b)

For the year 2007 the value of <em>x</em> is 10.

Compute the value of <em>y</em> for <em>x</em> = 10 as follows:

y=4.662+2.709x

  =4.662+(2.709\times10)\\=4.662+27.09\\=31.752\\\approx 31.8

Thus, the number of households using online banking at the beginning of 2007 is 31.8.

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