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Ksenya-84 [330]
3 years ago
11

Given two triangles △ABC and △A′B′C′ so that AB = A'B′ (Side), m∠A = m∠A′ (Angle), AC = A ′ C ′(Side). Then the triangles are co

ngruent.
USE STATEMENTS AND REASONS
Mathematics
1 answer:
vladimir1956 [14]3 years ago
8 0
The answer abc try it out hope it works
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F(x)=3x^2+6x-18 , find f(10)
lord [1]

Answer:

f(10)=342

Step-by-step explanation:

f(10)= 3(10)^2+6(10)-18

complete your exponet first and multiply 6(10)

f(10)=3(100)+60-18

multiply the 3(100)

f(10)=300+60-18

add and subtract all the numbers together

f(10)=342

5 0
3 years ago
What is 55/99 rounded to the nearest half
N76 [4]

Answer:1/2

Step-by-step explanation:

4 0
4 years ago
Find the value of x <br> 4 + 3x = 22 + x
guapka [62]

Answer:

x=9

Step-by-step explanation:

3x-x = 22-4

2x = 18

x = 18/2

x=9

Hope this helps!

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5 0
4 years ago
Read 2 more answers
AXYZ has vertices X(-4,2), Y(4.2), and Z(0, - 1). Is AXYZ scalene, isosceles, or equilateral?
ivolga24 [154]

Answer:

Isosceles triangle.

Step-by-step explanation:

In order to determine the nature of the triangle, we will need to get the sides XY, XZ and YZ using the distance formula;

For XY;

X(-4,2), Y(4.2)

XY = √(2-2)²(4-(-4)²)

XY = √(4+4)²

XY = √8²

XY = 8

For XZ;

X(-4,2), Z(0, - 1)

XZ = √(-1-2)²(0-(-4))²

XZ = √(-3)²+4²

XZ = √9+16

XZ = √25

XZ = 5

For XZ;

Y(4.2), Z(0, - 1)

YZ = √(-1-2)²(0-(4))²

YZ = √(-3)²+(-4)²

YZ = √9+16

YZ = √25

YZ = 5

Since XZ = YZ = 5, this shows that two sides are equal. Hence the triangle is an isosceles triangle.

NB: Isosceles triangle only have two of its sides and angles equal

5 0
3 years ago
Please answer the question in the photo that I have attatched. Please also explain how to solve it so I may solve the others.
Harrizon [31]

Answer:

9.85 is your answer

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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