All categories

2 years ago

One third of some number, x, decreased by six is thirty. What is the value of "X" ?

Mathematics

2 answers:

ziro4ka [17]2 years ago

7 0

Answer:

X = 42

Step-by-step explanation:

1/3 / 42 = 126

36 + 6 = 42

42 - 6 = 36

so the answer is 42

AnnZ [28]2 years ago

4 0

X=42 your very welcome

You might be interested in

A survey of 898 U.S. VCR owners found that 16% had VCR clocks that were currently blinking “12:00.” (Source: Wirthlin Worldwide)

yKpoI14uk [10]

In this case scenario, the population and sample would be:

Population : Collection of all US adult who own VCR

Sample : Collection 898 US adult who own VCR

<span>Therefore the answer to this is “False”</span>

<span>Hope this helps you!</span>

8 0

2 years ago

Read 2 more answers

I GIVE CROWN <br><br> HELP ONLY SERIOUS HELP NOT FOR POINTS

marin [14]

The answer will be -1/9

6 0

2 years ago

WILL GIVE BRAINLIEST!!

VMariaS [17]

Answer:

$A(-1,4)\to A''(-1,-1)$

$B(0,2)\to B''(1,0)$

$C(1,2)\to C''(1,1)$

$D(-2,4)\to D''(-1,2)$

Step-by-step explanation:

The given trapezoid has vertices at A(−1,4), B(0,2), C(1,2) and D(2,4).

The transformation rule for 90° counterclockwise rotation is

$(x,y)\to(-y,x)$

This implies that:

$A(-1,4)\to A'(-4,-1)$

$B(0,2)\to B'(-2,0)$

$C(1,2)\to C'(-2,1)$

$D(2,4)\to D'(-4,2)$

This is followed by a translation 3 units to the right.

This also has the rule: $(x,y)\to (x+3,y)$

$A'(-4,-1)\to A''(-1,-1)$

$B'(-2,0)\to B''(1,0)$

$C'(-2,1)\to C''(1,1)$

$D'(-4,2)\to D''(-1,2)$

Therefore:

$A(-1,4)\to A''(-1,-1)$

$B(0,2)\to B''(1,0)$

$C(1,2)\to C''(1,1)$

$D(-2,4)\to D''(-1,2)$

3 0

3 years ago

Please help me with this math question

scZoUnD [109]

Answer:

Step-by-step explanation:

$\bold{METHOD\ 1}\\\\6d=8e\qquad\text{divide both sides by 6}\\\\d=\dfrac{8}{6}e\to d=\dfrac{4}{3}e\\\\\text{Substitute it and}\ f=2e\ \text{to the ratio}\ d:e:f:\\\\\dfrac{4}{3}e:e:2e\qquad\text{cancel}\ e\\\\\dfrac{4}{3}:1:2\qquad\text{multiply by 3}\\\\\huge\boxed{4:3:6}$

$\bold{METHOD\ 2}\\\\6d=8e\qquad\text{divide both sides by 6}\\\\d=\dfrac{8}{6}e\qquad\text{divide both sides by}\ e\neq0\\\\\dfrac{d}{e}=\dfrac{4}{3}\to d:e=4:3\\\\2e=f\qquad\text{divide both sides by 2}\\\\e=\dfrac{f}{2}\to e=\dfrac{1}{2}f\qquad\text{divide both sides by}\ f\neq0\\\\\dfrac{e}{f}=\dfrac{1}{2}\to e:f=1:2\\\\\text{We have}\ d:e=4:3\ \text{and}\ e:f=1:2.$

$\text{We know}\ \dfrac{1}{2}=\dfrac{1\cdot3}{2\cdot3}=\dfrac{3}{6}\\\\\text{threfore}\ e:f=3:6\\\\\text{Now we have}\\\\\left\begin{array}{ccc}d:e=4:3\\e:f=3:6\end{array}\right\}\large{\boxed{d:e:f=4:3:6}}$

6 0

3 years ago

Why are asymptotes important in rational function graphs

leonid [27]

Answer:

when sketching the curves of functions.

Step-by-step explanation:

There is a wide range of graph that contain asymptotes and that includes rational functions, hyperbolic functions, tangent curves, and more. Asymptotes are important guides when sketching the curves of functions. This is why it’s important that we know the properties, general forms, and graphs of each of these asymptotes.

6 0

1 year ago