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Likurg_2 [28]
2 years ago
10

Which gives an equation for the line perpendicular to y = 2/3x + 1 that contains (0, 2) * O y = 3/2x + 2 O y = -3/2x + 2 O y = 3

/2x-2 O y = -3/2x-2​
Mathematics
1 answer:
andrew11 [14]2 years ago
7 0

Answer:

y = -\frac{3}{2}x + 2

Step-by-step explanation:

Equation of a line:

The equation of a line has the following format:

y = mx + b

In which m is the slope and b is the y-intercept(value of y when x = 0).

If two lines are perpendicular, the multiplication of their slopes is -1.

Contains (0, 2)

This means that b = 2. So

y = mx + 2

Finding the slope:

Perpendicular to y = 2/3x + 1 means that:

\frac{2m}{3} = -1

2m = -3

m = -\frac{3}{2}

So

y = -\frac{3}{2}x + 2

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A computer program contains one error. In order to find the error, we split the program into 6 blocks and test two of them, sele
Aleksandr-060686 [28]
There are \dbinom62 ways of selecting two of the six blocks at random. The probability that one of them contains an error is

\dfrac{\dbinom11\dbinom51}{\dbinom62}=\dfrac5{15}=\dfrac13

So X has probability mass function

f_X(x)=\begin{cases}\dfrac13&\text{for }x=1\\\\\dfrac23&\text{for }x=0\end{cases}

These are the only two cases since there is only one error known to exist in the code; any two blocks of code chosen at random must either contain the error or not.

The expected value of finding an error is then

\displaystyle\sum_{x=0}^1xf_X(x)=0\times\dfrac23+1\times\dfrac13=\dfrac13
7 0
3 years ago
the same type of television is being sold at two different stores. store A is selling the television for $800, which is $120 mor
svlad2 [7]

Answer: the selling price of the television at store B is $1360

Step-by-step explanation:

Assuming the selling price of the television at store B is represented by $B. Store A is selling the television for $800, which is $120 more than half the cost of the television at store B. The equation representing this situation is expressed as

800 = B/2 + 120

Multiplying the left hand side and the right hand side of the equation by 2, it becomes

1600 = B + 240

B = 1600 - 240

B = $1360

5 0
3 years ago
What is the slope of the line that passes through the points (6,7) and (4,1)?
Scorpion4ik [409]

Answer:

3

Step-by-step explanation:

m= y2 - y1/ x2 - x 1

(6, 7) (4, 1)

1-7= -6

4-6= -2

-6/-2 = 3

8 0
3 years ago
Start: 8:49pm. finish: 9:17 what is the answer calculate the duration​
tatuchka [14]

Answer:

1 minute and 8 seconds or 1:08

Step-by-step explanation:

by subtracting both at starting with 9:17-8:49 you will get a uneven decimal than you gonna have to give as much 60 seconds you can get out of it the 60 seconds equals a minute

8 0
3 years ago
New codes to destroy the First Order are known to exist. With probability 0.6, the codes are hidden by Leia; with probability 0.
elixir [45]

Answer: (a). 0.62 (b). 0.53

Step-by-step explanation:

Let us start by defining some events seen:

Given;

L rep the event that codes hidden Leia

BB represents the codes hidden in BB-8

H is the event that codes hidden by Hah

C-3PO rep the codes hidden in C3PO

Giving the probabilities, we have that

P(L)  =  probability that codes are hidden by Leia = 0.6

P(H) = probability that codes are hidden by Hah = 0.4

where P(BB/L) = 70/10 i.e 70%

P(C-3PO/L) = 1 - P(BB/L) = 1 - 7/10 = 3/10

Also, P(BB/H)  = 1/2 = P(C-3PO/H)

We can say that Han Solo is likely to hide them in aceta BB-8 and C-3PO

To begin,

(a). The question tell us to find the probability that the codes are with BB-8.

First of all, we find P(BB).

P(BB) = P(L)*P(BB/L) + P(H)*P(BB/H)

solving this we get

P(BB) = 0.6*7/10 + 0.4*1/2 = 0.62

Therefore,  the probability that the codes are with BB-8 = 0.62

(b). The second question says;

Given that the codes are with C-3PO, what is the probability the codes were hidden by Han Solo?

This tell us to find P(H/C-3PO)

P(H/C-3PO) = P(C-3PO/H)*P(H) / P(C-3PO/H) + P(C-3PO/L)*P(L)

inputting the values gives us;

P(H/C-3PO) = 1/2 * 0.4 / ( 1/2 *0.4 + 3/10 *0.6) = 0.53

SO we have that the probability the codes were hidden by Han Solo = 0.53

cheers I hope this was helpful!!

3 0
3 years ago
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