Question

Which gives an equation for the line perpendicular to y = 2/3x + 1 that contains (0, 2) * O y = 3/2x + 2 O y = -3/2x + 2 O y = 3/2x-2 O y = -3/2x-2​

Answer 1

Answer:

$y = -\frac{3}{2}x + 2$

Step-by-step explanation:

Equation of a line:

The equation of a line has the following format:

$y = mx + b$

In which m is the slope and b is the y-intercept(value of y when x = 0).

If two lines are perpendicular, the multiplication of their slopes is -1.

Contains (0, 2)

This means that $b = 2$. So

$y = mx + 2$

Finding the slope:

Perpendicular to y = 2/3x + 1 means that:

$\frac{2m}{3} = -1$

$2m = -3$

$m = -\frac{3}{2}$

So

$y = -\frac{3}{2}x + 2$