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Step2247 [10]
3 years ago
14

How many times can you put 2500cm2 into 15m2?

Mathematics
2 answers:
Ronch [10]3 years ago
8 0
Convert 2500 cm² into mm²:
2500 cm · cm x \frac{1 m}{100 cm} x  \frac{1 m}{100 cm} = .25 m²

Next, divide:
\frac{15  m^{2}}{.25  m^{2}} = 60

Answer: 60
Svetach [21]3 years ago
3 0
You can put 2500cm2 into 15m2 60 times
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Select all of the equations that have a solution of 4.
just olya [345]

Answer:

A, D

Step-by-step explanation:

A. 5x = 20

divide by 5 on both sides

x = 4

D. x/2 = 2

multiply both sides by 2

x = 4

B and C would equal -4

E would equal 64

8 0
3 years ago
Read 2 more answers
In the following problem, check that it is appropriate to use the normal approximation to the binomial. Then use the normal dist
WARRIOR [948]

Answer:

(a) The probability that more than 180 will take your free sample is 0.1056.

(b) The probability that fewer than 200 will take your free sample is 0.9997.

(c) The probability that a customer will take a free sample and buy the product is 0.2184.

(d) The probability that between 60 and 80 customers will take the free sample and buy the product is 0.8005.

Step-by-step explanation:

We are given that about 56% of all customers will take free samples. Furthermore, of those who take the free samples, about 39% will buy what they have sampled.

The day you were offering free samples, 303 customers passed by your counter.

Firstly, we will check that it is appropriate to use the normal approximation to the binomial, that is;

Is np > 5  and  n(1-p) > 5

In our question, n = sample of customers = 303

                          p = probability that customers will take free sample = 56%

So, np = 303 \times 0.56 = 169.68 > 5

     n(1-p) = 303 \times (1-0.56) = 133.32 > 5

Since, both conditions are satisfied so it is appropriate to use the normal approximation to the binomial.

Now, mean of the normal distribution is given by;

        Mean, \mu = n \times p = 169.68

Also, the standard deviation of the normal distribution is given by;

       Standard deviation, \sigma = \sqrt{n \times p \times (1-p)}

                                            = \sqrt{303 \times 0.56 \times (1-0.56)} = 8.64

Let X = Number of people who will take your free sample

The z score probability distribution for normal distribution is given by;

                           Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

(a) The probability that more than 180 will take your free sample is given by = P(X > 180) = P(X > 180.5)     {Using continuity correction}

        P(X > 180.5) = P( \frac{X-\mu}{\sigma} > \frac{180.5-169.68}{8.64} ) = P(Z > 1.25) = 1 - P(Z < 1.25)

                                                                   = 1 - 0.8944 = <u>0.1056</u>

(b) The probability that fewer than 200 will take your free sample is given by = P(X < 200) = P(X < 199.5)     {Using continuity correction}

        P(X < 199.5) = P( \frac{X-\mu}{\sigma} < \frac{199.5-169.68}{8.64} ) = P(Z < 3.45) = <u>0.9997</u>

(c) We are given in the question that of those who take the free samples, about 39% will buy what they have sampled, this means that we have;

     P(Buy the product / taken a free sample) = 0.39

So, Probability(customer will take a free sample and buy the product) = P(customer take a free sample) \times P(Buy the product / taken a free sample)

     = 0.56 \times 0.39 = <u>0.2184</u>

(d) Now our mean and standard deviation will get changed because the probability of success now is p = 0.2184 but n is same as 303.

So, Mean, \mu = n \times p = 303 \times 0.2184 = 66.18

Standard deviation, \sigma = \sqrt{n \times p \times (1-p)}

                                    = \sqrt{303 \times 0.2184 \times (1-0.2184)} = 7.192

Now, the probability that between 60 and 80 customers will take the free sample and buy the product is given by = P(60 < X < 80) = P(59.5 < X < 80.5)         {Using continuity correction}

     P(59.5 < X < 80.5) = P(X < 80.5) - P(X \leq 59.5)

     P(X < 80.5) = P( \frac{X-\mu}{\sigma} < \frac{80.5-66.18}{7.192} ) = P(Z < 1.99) = 0.9767

     P(X \leq 59.5) = P( \frac{X-\mu}{\sigma} \leq \frac{59.5-66.18}{7.192} ) = P(Z \leq -0.93) = 1 - P(Z < 0.93)

                                                            = 1 - 0.8238 = 0.1762

Therefore, P(59.5 < X < 80.5) = 0.9767- 0.1762 = <u>0.8005.</u>

4 0
3 years ago
What is the answer for g=ca, for a
vodomira [7]

Answer:

a=g/c

or

g/c=a

Step-by-step explanation:

divide c on both sides and you will get a=g/c or g/c=a

3 0
2 years ago
X<br> 451<br> 412<br> 451<br> Find the value of x.<br> A. 42<br> 2<br> B. 4<br> C. 43<br> D. 43
marysya [2.9K]

Answer:

B. 4

Step-by-step explanation:

cos(45°) = x/4√2

√2/2 = x/4√2

x = 4√2•√2/2

x = 4

8 0
3 years ago
If the ball rolled 20 meters in 5 secoundes whats its speed
MaRussiya [10]

Answer:

4 meters/ sec

Step-by-step explanation:

20/5 = 4 Lol

Pls mark brainliest

8 0
2 years ago
Read 2 more answers
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