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d1i1m1o1n [39]
3 years ago
11

Let X1, . . . ,Xn be an i.i.d. random sample from a N(0, 1) population. Define Y1 = 1 n n X i=1 Xi , Y2 = 1 n n X i=1 |Xi| . Cal

culate E(Y1) and E(Y2), and compare them.
Mathematics
1 answer:
nalin [4]3 years ago
8 0

For each 1\le i\le n, E[X_i]=0, so that

\displaystyle E[Y_1]=E\left[\frac1n\sum_{i=1}^nX_i\right]=\frac1n\sum_{i=1}^nE[X_i]=0

Meanwhile,

\displaystyle E[Y_2]=\frac1n\sum_{i=1}^nE[|X_i|]

Each of the X_i have PDF

f_{X_i}(x)=\dfrac1{\sqrt{2\pi}}e^{-x^2/2}

for x\in\Bbb R. From this we get

E[|X_i|]=\displaystyle\frac1{\sqrt{2\pi}}\int_{-\infty}^\infty|x|e^{-x^2/2}\,\mathrm dx=\sqrt{\frac2\pi}\int_0^\infty xe^{-x^2/2}\,\mathrm dx=\sqrt{\frac2\pi}

\implies E[Y_2]=n\sqrt{\dfrac2\pi}

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Alchen [17]

Answer:

$0.19.

Step-by-step explanation:

Unit rate / ounce = 2.66 / 14

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5 0
3 years ago
These are 256 in a box.these are composed of apples,oranges,and ponkans. If their ratio is 3:5:6 respectively.how many apples ar
nataly862011 [7]

x is some whole number so 3x represents the number of apples, 5x is the number of oranges and 6x is the number of ponkans. The numbers 3x, 5x and 6x are also whole numbers as well. They add up to 256 total pieces of fruit. Solve the equation below for x

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4 0
3 years ago
Jylene and her brother had a total of $35.19 to buy school supplies. Jylene's school supplies cost
cricket20 [7]

Answer:

13.31

Step-by-step explanation:

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I assume slightly more than $9 is .1

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5 0
3 years ago
What’s a solution set
solong [7]

It's the group of correct solutions to a given problem.

Imagine you have apples, pears and peaches you're asked <em>"what fruits do you have"</em>? Your solution set would be {apple, pear, peach}.

3 0
3 years ago
A: 15<br> B: 21 <br> C: 26<br> D: 105
Hatshy [7]

Answer:B=21

Step-by-step explanation:

it is because combined J an N are 105 across from that is the same so x is 21 because 5(x) = 21 u do 105 divided by 5 to get the answer

4 0
3 years ago
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