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d1i1m1o1n [39]
3 years ago
11

Let X1, . . . ,Xn be an i.i.d. random sample from a N(0, 1) population. Define Y1 = 1 n n X i=1 Xi , Y2 = 1 n n X i=1 |Xi| . Cal

culate E(Y1) and E(Y2), and compare them.
Mathematics
1 answer:
nalin [4]3 years ago
8 0

For each 1\le i\le n, E[X_i]=0, so that

\displaystyle E[Y_1]=E\left[\frac1n\sum_{i=1}^nX_i\right]=\frac1n\sum_{i=1}^nE[X_i]=0

Meanwhile,

\displaystyle E[Y_2]=\frac1n\sum_{i=1}^nE[|X_i|]

Each of the X_i have PDF

f_{X_i}(x)=\dfrac1{\sqrt{2\pi}}e^{-x^2/2}

for x\in\Bbb R. From this we get

E[|X_i|]=\displaystyle\frac1{\sqrt{2\pi}}\int_{-\infty}^\infty|x|e^{-x^2/2}\,\mathrm dx=\sqrt{\frac2\pi}\int_0^\infty xe^{-x^2/2}\,\mathrm dx=\sqrt{\frac2\pi}

\implies E[Y_2]=n\sqrt{\dfrac2\pi}

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Cammie can mow 1/2 acre in 25 minutes. If her rate is constant, Cammie says she can mow 1 1/4 acres in one hour. Is Cammie corre
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Convert the mixed number to an impoper fraction:

1. Multiply the whole number part by the denominator of the fraction and add the product to the numerator.

2. The denominator does not change.

Then:

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Let be "x" the acres Cammie can mow in one hour.

You know that she can mow \frac{1}{2}\ acre in 25 minutes, then you can set up the following proportion (Remember that 1 hour has 60 minutes):

\frac{\frac{1}{2}}{25}=\frac{x}{60}

Solving for "x", you get:

\frac{\frac{1}{2}}{25}=\frac{x}{60}\\\\(60)(\frac{1}{50})=x\\\\x=\frac{6}{5}

Convert from improper fraction to mixed number:

1. When you divide 6 by 5, the quotient is 1. This will be the whole number part.

2. The remainder is 1. This will be the numerator.

3. The denominator does not change.

Then:

x=1\frac{1}{5}

Therefore, she can mow  1\frac{1}{5}\ acres in one hour.

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a parallel line will also be horizontal with equation

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a line perpendicular to the given line will be a vertical line with equation

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