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3 years ago

Help me pls thx ......

Mathematics

2 answers:

melisa1 [442]3 years ago

8 0

Answer:

6x2-2x

Step-by-step explanation:

DIA [1.3K]3 years ago

5 0

Its 6x2-2x yea thats all

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How do i prove 2sec^2x-2sec^2xsin^2-sin^2x-cos^2x=1

kramer

$2\sec^2x-2\sec^2x\sin^2x-\sin^2x-\cos^2x=2\sec^2x(1-\sin^2x)-(\sin^2x+\cos^2x)$

Since $\sin^2x+\cos^2x=1$ , you have

$2\sec^2x(1-\sin^2x)-(\sin^2x+\cos^2x)=2\sec^2x\cos^2x-1$

and since $\sec x=\dfrac1{\cos x}$ , you end up with $2-1=1$ .

6 0

3 years ago

Consider a triangular prism. The triangular end has a base of 4 cm and height of 5 cm. The length of each side is 6 cm and the h

AysviL [449]

B.)10 inches
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you need to plug in 10
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thats if you don't know what to do
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3 years ago

The amount of time it takes Ariana to do a math problem is continuous and uniformly distributed between 38 seconds and 79 second

solniwko [45]

Answer:

29.27% probability that it takes Ariana between 58 and 70 seconds to do a math problem

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X between c and d, d being greater than c, is given by the following formula:

$P(c \leq X \leq d) = \frac{d-c}{b-a}$

Uniformly distributed between 38 seconds and 79 seconds.

This means that $a = 38, b = 79$

What is the probability that it takes Ariana between 58 and 70 seconds to do a math problem

$c = 58, d = 70$

$P(58 \leq X \leq 70) = \frac{70 - 58}{79 - 38} = 0.2927$

29.27% probability that it takes Ariana between 58 and 70 seconds to do a math problem

4 0

3 years ago

Avery wants to make a triangular garden but needs to fence it in to keep rabbits out.How can she figure out how much fencing to

nexus9112 [7]

Find the perimeter of the garden find out what kind of triangle the garden is for example if it is a right triangle it has to equal up to 90.

To find the area remember that A=b•h2 as a=area

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3 years ago

Find the greates common factor of the following monomials:2r^4s^2 and 36r^4s^3

ki77a [65]

The greatest common factor is 2 $r^{4} s^{2}$

This is because we start by taking the largest factor that goes into both coefficients. Since the first coefficient is 2, we have to try 2 and 1. Since 2 is larger and goes into 36 evenly, we use that.

Then we use the smallest number of each variable. There are 4 r's in both equations. So, that is the number that we take. There are 2 s's in the first term, so we take that number.

6 0

4 years ago