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3 years ago

Help me pls thx ......

Mathematics

2 answers:

melisa1 [442]3 years ago

8 0

Answer:

6x2-2x

Step-by-step explanation:

DIA [1.3K]3 years ago

5 0

Its 6x2-2x yea thats all

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Is 0.74 greater than 3/2

KonstantinChe [14]

Answer:

Step-by-step explanation:

if you simplify 3/2 to a decimal, you get 1.5

comparing 0.74 to 3/2 we can conclude that 3/2 is in fact greater

7 0

2 years ago

In a certain region, there is a 0.1 probability that any checked passerine bird's nest will

mamaluj [8]

Answer:

Probability of at least two cuckoo eggs is 0.738.

Step-by-step explanation:

probability of cuckoo egg = 0.1

probability of not a cuckoo egg = 1 - 0.1 = 0.9

Probability of at least two cuckoo eggs is

= Probability of two cuckoo eggs x probability of 1 not cuckoo egg +

probability of three cuckoo eggs

= 0.1 x 0.1 x 0.9 + 0.9 x 0.9 x 0.9

= 0.009 + 0.729

= 0.738

5 0

3 years ago

Can someone please help me with my maths question

DIA [1.3K]

Answer:

$a. \ \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$b. \ \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

Step-by-step explanation:

The question relates with rules of indices

(a) The give expression is presented as follows;

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}$

By expanding the expression, we get;

$\dfrac{m^3 \times n^{-8} \times 5^4 \times m^4}{\left 3^3 \times m^6 \times n^3}$

Collecting like terms gives;

$\dfrac{m^{(3 + 4 - 6)} \times 5^4}{ 3^3 \times n^{3 + 8}} = \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}= \dfrac{625 \cdot m}{27 \cdot n^{11}}$

(b) The given expression is presented as follows;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \div (x \cdot y^n)^4$

Therefore, we get;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n}$

Collecting like terms gives;

$x^{3 \cdot m + 2 - 4} \times \left (y^{3 \cdot n - 3 -4 \cdot n}} \right ) = x^{3 \cdot m - 2} \times \left (y^{ - 3 -n}} \right ) = x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right )$

$x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right ) = \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n} =\dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

4 0

3 years ago

Meg used this table to track the average attendance from month to month at her theater for five months. A 5-column table with 1

White raven [17]

Answer:

B - Her monthly average would have increased by $19.57. ... Katie works as a waitress and records her monthly tips in the table shown below. If Katie decided not to work the month of November, how would her five month average compare to her six month ... Lisa is currently taking physics as one of her electives in school.

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

The sum of three consecutive integers is −42. find the three integers.

erica [24]

Let the integers be x - 1, x and x + 1, then
x - 1 + x + x + 1 = -42
3x = -42
x = -42/3 = -14

The three consectutive integers are -15, -14 and -13

4 0

3 years ago