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Anna35 [415]
3 years ago
10

The probability distribution for a random variable x is given in the table X: -5,-3,-2,0,2,3 Probability: .17,.13,.33,.16,.11,.1

0 Find the probability that -2<_x<_2

Mathematics
1 answer:
Ivan3 years ago
4 0

Answer:

0.6 probability that -2 \leq x \leq 2

Step-by-step explanation:

The probability distribution is given in the table.

Probability that x is between -2 and 2.

Between -2 and 2, inclusive, we have -2, 0 and 2. So

P(-2 \leq x \leq 2) = P(X = -2) + P(X = 0) + P(X = 2)

From the table:

P(X = -2) = 0.33, P(X = 0) = 0.16, P(X = 2) = 0.11. So

P(-2 \leq x \leq 2) = P(X = -2) + P(X = 0) + P(X = 2) = 0.33 + 0.16 + 0.11 = 0.60

0.6 probability that -2 \leq x \leq 2

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8 0
3 years ago
What is the value of x?
Nikolay [14]
Answer: 7 centimeters 

Explanation:

Let triangle ABC and triangle CDE form a bow tie such that 
     - triangle ABC is smaller than triangle CDE
     - Segment AC and segment CD are the north sides
     - Segment BC and segment CE are the bottom sides
     - AC = 6, CD = 42, CE = 36, BC = x

Since angle ACB and angle ECD are formed by intersecting segment AE and segment BD at point C, they are vertical angles. (See the attached picture) So, angle ACB and angle ECD are congruent. 

Moreover when we form our bowtie, point A is in the north side and point E is in the bottom sides and this implies that angle BAC and angle CED are alternate interior angles as shown in the attached figure. 

Since it is given in the problem that alternating interior angle are congruent, angle BAC and angle CED are congruent. 

Now, we have the following pairs of angles in triangle ABC and triangle CDE that are congruent:

- angle BAC and angle CED
- angle ACB and angle ECD

By AA Similarity theorem, when we have two pairs of congruent angles for two triangles, then the two triangles are similar. So, triangle ABC and triangle CDE are similar.

In similar triangles, the sides that are opposite to the congruent angles are proportional to each other. So, 

\frac{BC}{CD}  =  \frac{AC}{CE} &#10;&#10;&#10;    (1)

Since AC = 6, CD = 42, CE = 36, BC = x, we can substitute these values to equation (1). So, equation (1) becomes

\frac{x}{42} = \frac{6}{36}
\frac{x}{42} = \frac{1}{6}  (2)

SInce we are solving for x, we can multiply both sides of equation (2) by the denominator at the left side which is 42 so that

x = 42(1/6)
x = 7 centimeters

8 0
3 years ago
Who knows how to do this
Ivan
Area by Heron's formula:
semiperimeter = (15 + 20 + 25)/2 = 60/2 = 30 cm
&#10;Area = \sqrt{30(30-15)(30-20)(30-25)}= \sqrt{30 \cdot5\cdot10\cdot15}= \\\\ {} \ \ \ \ \ \ =\sqrt{22500} =150 \ cm^2

The formula of the area of a triangle: Area = 1/2 * base * height
1/2 * 25 * height = 150
12.5 * height = 150
height = 150/12.5
height = 12 cm
3 0
3 years ago
Which formula can be used to find the nth term of the geometric sequence below? 1/6,1,6,36
IRINA_888 [86]
Ratio = 1÷1/6 = 6÷1 = 36÷6 = 6

nth term

a_{n} = a r^{n-1} (where a is the first term)

a_{n} =  \frac{1}{6}  6^{n-1}

7 0
3 years ago
Read 2 more answers
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