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3 years ago

Factor completely. 3x^2+30x+75=

2 answers:

7 0

You write the problem as a mathematical expression
3x^2 + 30x + 75 =
Factor: 3 out of 3x^2 + 30x + 75.

3 (x2 + 10x + 25)

Factor using the perfect square rule.
And then your answer should be 3 ( x + 5) ^2

Katen [24]3 years ago

6 0

Answer:

3(x+5)(x+5)

Step-by-step explanation:

Factor 3x^2+30x+75

3x^2+30x+75

=3(x+5)(x+5)

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A United Nations report shows the mean family income for Mexican migrants to the United States is $27,000 per year. A FLOC (Farm

disa [49]

Answer:

We conclude that the mean family income for Mexican migrants to the United States is $27,000 per year and the provided information is consistent with the United Nations report.

Step-by-step explanation:

We are given that a United Nations report shows the mean family income for Mexican migrants to the United States is $27,000 per year.

A FLOC evaluation of 25 Mexican family units reveals a mean to be $30,000 with a sample standard deviation of $10,000.

Let $\mu$ = true mean family income for Mexican migrants.

So, Null Hypothesis, $H_0$ : $\mu$ = $27,000 {means that the mean family income for Mexican migrants to the United States is $27,000 per year}

Alternate Hypothesis, $H_A$ : $\mu$ $\neq$ $27,000 {means that the mean family income for Mexican migrants to the United States is different from $27,000 per year}

The test statistics that would be used here One-sample t test statistics as we don't know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean family income = $30,000

s = sample standard deviation = $10,000

n = sample of Mexican family = 25

So, the test statistics = $\frac{30,000-27,000}{\frac{10,000}{\sqrt{25} } }$ ~ $t_2_4$

= 1.50

The value of t test statistics is 1.50.

Since, in the question we are not given the level of significance so we assume it to be 5%. Now, at 5% significance level the t table gives critical values of -2.064 and 2.064 at 24 degree of freedom for two-tailed test.

Since our test statistic lies within the range of critical values of t, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the mean family income for Mexican migrants to the United States is $27,000 per year and the provided information is consistent with the United Nations report.

4 0

3 years ago

A triangle has two sides that measure 4ft and 3ft. Which could be the measure of the third side?

Nezavi [6.7K]

The measure of the third side must be less than the sum of the other two. That property is valid for all triangles.

For this question, call x the measure of the third side. So you must have

x < 4 + 3

x < 7 ft

The only option that satisfies the condition above is

option A) 5 ft.

I hope this helps. =)

7 0

3 years ago

Read 2 more answers

Jason observed a large art sculpture in a local park and wanted to know its height, but the sculpture was much taller than he co

ZanzabumX [31]

The art sculpture was 70 inches aka 5.9feet tall and if we round it well it would be 6feet so that would be its highest piont

6 0

3 years ago

Read 2 more answers

For a fair coin, suppose you toss the coin 100 times.

Natasha_Volkova [10]

Using the normal distribution, it is found that there is a 0.0005 = 0.05% probability of getting more than 66 heads.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The binomial distribution is the probability of x successes on n trials, with p probability of a success on each trial. It can be approximated to the normal distribution with $\mu = np, \sigma = \sqrt{np(1-p)}$ .

For the binomial distribution, the parameters are given as follows:

n = 100, p = 0.5.

Hence the mean and the standard deviation of the approximation are given as follows:

$\mu = np = 100(0.5) = 50$ .

$\sigma = \sqrt{np(1-p)} = \sqrt{100(0.5)(0.5)} = 5$

Using continuity correction, the probability of getting more than 66 heads is P(X > 66 + 0.5) = P(X > 66.5), which is one subtracted by the p-value of Z when X = 66.5.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{66.5 - 50}{5}$

Z = 3.3

Z = 3.3 has a p-value of 0.9995.

1 - 0.9995 = 0.0005.

0.0005 = 0.05%

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

6 0

1 year ago

At Mr. Hynd's ranch, there are 35 chickens and 20 cows. What is the ratio of the number of cows to the

Anton [14]

7/4 because you simplify

5 0

3 years ago