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IrinaVladis [17]
3 years ago
10

Find a polynomial with a degree of 3, and the zeros 1,7, & -4 with no other zeros.

Mathematics
1 answer:
jarptica [38.1K]3 years ago
5 0

Answer:

f(x)=(x+4)(x-7)(x-1)

Step-by-step explanation:

zeroes are when you plug in that x value and get y=0

therefore if you set x = that number and solve for 0 you get a "function"

multiplying these together will yield the complete 3rd degree polynomial

x = 1

x-1=0

x=7

x-7=0

x=-4

x+4=0

f(x)=(x+4)(x-7)(x-1)

If needed you could expand but I'm too lazy

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HELP ME MATH ILL GIVE YOU BRAINLIEST
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Answer:

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  • end behavior: as x approaches -∞, f(x) approaches -∞.

Step-by-step explanation:

I like to use a graphing calculator for finding the zeros of higher order polynomials. The attachment shows them to be at x = -3, -1, +2.

__

The zeros can also be found by trial and error, trying the choices offered by the rational root theorem: ±1, ±2, ±3, ±6. It is easiest to try ±1. Doing so shows that -1 is a root, and the residual quadratic is ...

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For any odd-degree polynomial with a positive leading coefficient, the sign of the function will match the sign of x when the magnitude of x gets large. Thus as x approaches negative infinity, so does f(x).

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