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Fiesta28 [93]
3 years ago
8

PLEASE HELP DUE IN A FEW MINUTES PLEASE HELP!!!!

Mathematics
2 answers:
lisov135 [29]3 years ago
8 0

Answer:

A: (1,3)

B: (3,2)

C: (-2,1)

D: (-4,-2)

E: (-2,-4)

F: (-1,-3)

G: (2,-1)

H: (4,-3)

J: (0,-2)

anzhelika [568]3 years ago
4 0

Answer:

A=1,3

B=3,2

C=-2,1

D=-2,4

E=-4,-2

F=-1,-3

G=2,-1

H=4,-3

J=0,-2

K=2,0

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Determine the truth value of each of these statements if thedomainofeachvariableconsistsofallrealnumbers.
hoa [83]

Answer:

a)TRUE

b)FALSE

c)TRUE

d)FALSE

e)TRUE

f)TRUE

g)TRUE

h)FALSE

i)FALSE

j)TRUE

Step-by-step explanation:

a) For every x there is y such that  x^2=y:

 TRUE

This statement is true, because for every real number there is a square         number of that number, and that square number is also a real number. For example, if we take 6.5, there is a square of that number and it equals 39.0625.

b) For every x there is y such that  x=y^2:

 FALSE

For example, if x = -1, there is no such real number so that its square equals -1.

c) There is x for every y such that xy = 0

 TRUE

If we put x = 0, then for every y it will be xy=0*y=0

d)There are x and y such that x+y\neq y+x

 FALSE

There are no such numbers. If we rewrite the equation we obtain an incorrect statement:

                                   x+y \neq y+x\\x+y - y-y\neq 0\\0\neq 0

e)For every x, if   x \neq 0  there is y such that xy=1:

 TRUE

The statement is true. If we have a number x, then multiplying x with 1/x (Since x is not equal to 0 we can do this for ever real number) gives 1 as a result.

f)There is x for every y such that if y\neq 0 then xy=1.

TRUE

The statement is equivalent to the statement in e)

g)For every x there is y such that x+y = 1

TRUE

The statement says that for every real number x there is a real number y such that x+y = 1, i.e. y = 1-x

So, the statement says that for every real umber there is a real number that is equal to 1-that number

h) There are x and y such that

                                  x+2y = 2\\2x+4y = 5

We have to solve this system of equations.

From the first equation it yields x=2-2y and inserting that into the second equation we have:

                                   2(2-2y)+4y=5\\4-4y+4y=5\\4=5

Which is obviously false statement, so there are no such x and y that satisfy the equations.

FALSE

i)For every x there is y such that

                                     x+y=2\\2x-y=1

We have to solve this system of equations.

From the first equation it yields x=2-y  and inserting that into the second equation we obtain:

                                        2(2-y)-y=1\\4-2y-y=1\\4-3y=1\\-3y=1-4\\-3y=-3\\y=1

Inserting that back to the first equation we obtain

                                            x=2-1\\x=1

So, there is an unique solution to this equations:

x=1 and y=1

The statement is FALSE, because only for x=1 (and not for every x) exists y (y=1) such that

                                         x+y=2\\2x-y=1

j)For every x and y there is a z such that

                                      z=\frac{x+y}{2}

TRUE

The statament is true for all real numbers, we can always find such z. z is a number that is halway from x and from y.

5 0
3 years ago
In the diagram, the radius of the outer circle is
JulijaS [17]

the value of x is 8 cm.

<u>Step-by-step explanation:</u>

Correct Question : In the diagram, the radius of the outer circle is 2x cm and the radius of the inside circle is 6 cm. The area of the shaded region is 220π cm2. What is the value of x? Enter your answer in the box.

We have ,

the area of a circle =  πr²

the outer circle area = \pi(2x)^2 =4\pi x^2

the inside circle area = \pi (6)^2= 36\pi

According to Question,

the outer circle area - the inside circle area = he shaded region

⇒ \pi (4x^2)-36\pi =220\pi

⇒ x^2-9 =55

⇒ x^2=64

⇒x =\sqrt{64}=8

Therefore , the value of x is 8 cm.

5 0
2 years ago
Translate question into an equation, let x be unknown number 6.4 is 90% of what number?
lisov135 [29]
1 \% = \frac{1}{100}\\ \\90 \% * x =6.4  \\ \\\frac{90}{100}x=6.4  \\ \\\frac{9 }{10 }x=6.4 \ \ *(\frac{10}{9})\\ \\x= 6.4 *\frac{10}{9}\\ \\x=\frac{64}{9}\\ \\x = 7\frac{1}{9}
8 0
3 years ago
Read 2 more answers
What is the range of this relation? ​
gayaneshka [121]

Answer:

{- 1, 0, 4 }

Step-by-step explanation:

the range is the y- coordinates of the plotted points

the coordinates of the points are

(- 4, - 1 ) , (1, 0 ) , (1, 4 ) with y- coordinates - 1, 0, 4

then range is { - 1, 0, 4 }

6 0
2 years ago
Can you help me please
grigory [225]

m is 43



add my instagarm @jessica.letendre

5 0
3 years ago
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