Answer:
21
Step-by-step explanation:
i worked out the problem
Answer:
sec 0 = 5/(2√6)
Step-by-step explanation:
sin 0 = -1/5
Fourth quadrant Cos positive Rest negative
cos²0 + sin²0 = 1
cos²0 = 1-sin²0
cos²0 = 1 - (1/5)²
cos²0 = 1- 1/25
cos²0 = 24/25
cos0 = ±(2√6)/5
quadrant IV cos is positive.
Therefore cos0 = (2√6)/5
Now, sec0 = 1/cos0
sec0 = 1/{(2√6)/5)}
sec0 = 5/(2√6)
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Hope it helps
Answer:
If you consider what the slope looks like for a vertical line, it is an infinite slope. What that means is that you cannot have a y-value in your equation:
x = 3
This x-value would be a vertical line that passes through all y-values for x = 3. So you can replace them in (3, y) with any value, and it will be included in the linear equation x = 3.
Answer:
260°
Step-by-step explanation:
∠RPS +∠PSR +∠SRP= 180° (∠ sum of △PRS)
∠RPS +45° +60°= 180°
∠RPS +105°= 180°
∠RPS= 180° -105°
∠RPS= 75°
Let's focus on quadrilateral PQTU.
Sum of interior angles= (n -2) ×180°, where n is the number of sides
∠QPU
= ∠RPS +∠TPU
= 75° +25°
= 100°
Sum of interior angles= (4 -2) ×180°
m +n +p +100°= 2 ×180°
m +n +p +100°= 360°
m +n +p
= 360° -100°
= 260°