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Montano1993 [528]
3 years ago
7

HELP ASAP PLS

Mathematics
2 answers:
Sergeu [11.5K]3 years ago
8 0
I’ll try to find it
lakkis [162]3 years ago
3 0

Answer:

Ill try not to sure what I can do though!

Step-by-step explanation:

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Which three values are greater than
solniwko [45]

Answer:

3/4 is greater than 1/2

45% = 9/20 is less than 1/2

1/3 is less than 1/2

0.62 is greater than 1/2

59% = 59/100 is greater than 1/2

0.315 is less than 1/2

So, A, D and E are greater than 1/2

Hope this helps!

6 0
3 years ago
What is the equation of the following graph in vertex form?
anygoal [31]

Answer:

I think the answer is 0,8

6 0
3 years ago
I'm stuck what is 15% of 32
Len [333]
In math, 'of' means 'multiplied by,' so 15% of 32 translates to '15% * 32.'
Now solve the equation:
x = 15% * 32
x = .15 * 32
x = 4.8
6 0
2 years ago
If f(x)=X-3/x and g(x) = 5x – 4, what is the domain of (fog)(x)?<br><br><br> NEED HELP FAST!!
dedylja [7]

Answer:

Step-by-step explanation:

This is function composition. We will take the g function and plug it into the f function wherever we see an x. That will look like this when it's done but before it's simplified:

f(g(x))=\frac{5x-4-3}{5x-4} and that can be simplified down to

f(g(x))=\frac{5x-7}{5x-4}

The domain of this function will be all real numbers EXCEPT for the one(s) that cause the denominator to become undefined. Set the denominator equal to 0 and solve for x:

5x - 4 = 0 so

5x = 4 and

x = 4/5

In other words, D = {x | x ≠ 4/5}

6 0
3 years ago
What is the expansion of (3+x)^4
Vlad1618 [11]

Answer:

\left(3+x\right)^4:\quad x^4+12x^3+54x^2+108x+81

Step-by-step explanation:

Considering the expression

\left(3+x\right)^4

Lets determine the expansion of the expression

\left(3+x\right)^4

\mathrm{Apply\:binomial\:theorem}:\quad \left(a+b\right)^n=\sum _{i=0}^n\binom{n}{i}a^{\left(n-i\right)}b^i

a=3,\:\:b=x

=\sum _{i=0}^4\binom{4}{i}\cdot \:3^{\left(4-i\right)}x^i

Expanding summation

\binom{n}{i}=\frac{n!}{i!\left(n-i\right)!}

i=0\quad :\quad \frac{4!}{0!\left(4-0\right)!}3^4x^0

i=1\quad :\quad \frac{4!}{1!\left(4-1\right)!}3^3x^1

i=2\quad :\quad \frac{4!}{2!\left(4-2\right)!}3^2x^2

i=3\quad :\quad \frac{4!}{3!\left(4-3\right)!}3^1x^3

i=4\quad :\quad \frac{4!}{4!\left(4-4\right)!}3^0x^4

=\frac{4!}{0!\left(4-0\right)!}\cdot \:3^4x^0+\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1+\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2+\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3+\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4

=\frac{4!}{0!\left(4-0\right)!}\cdot \:3^4x^0+\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1+\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2+\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3+\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4

as

\frac{4!}{0!\left(4-0\right)!}\cdot \:\:3^4x^0:\:\:\:\:\:\:81

\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1:\quad 108x

\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2:\quad 54x^2

\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3:\quad 12x^3

\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4:\quad x^4

so equation becomes

=81+108x+54x^2+12x^3+x^4

=x^4+12x^3+54x^2+108x+81

Therefore,

  • \left(3+x\right)^4:\quad x^4+12x^3+54x^2+108x+81
6 0
3 years ago
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