Question

A carton has a length of fraction 2 and 2 over 3 feet, width of fraction 1 and 1 over 8 feet, and height of fraction 1 and 1 over 5 feet. What is the volume of the carton? (5 points) fraction 3 and 3 over 5 cubic feet fraction 4 and 1 over 5 cubic feet fraction 5 and 2 over 5 cubic feet fraction 7 and 1 over 5 cubic feet

Answer 1

Answer:

Option A)

The volume of carton is $3\frac{3}{5}\text{ cube feet}$.

Step-by-step explanation:

We are given the following information in the question:

Length of carton =

$2\displaystyle\frac{2}{3}\text{ feet}$

Width of carton =

$1\displaystyle\frac{1}{8}\text{ feet}$

Height of carton =

$1\displaystyle\frac{1}{5}\text{ feet}$

Formula:

$\text{Volume of cone} = \text{Length}\times \text{Width}\times \text{Heigth}$

Putting the values:

$\text{Volume} = 2\displaystyle\frac{2}{3}\times 1\displaystyle\frac{1}{8}\times 1\displaystyle\frac{1}{5}\\\\= \frac{8}{3}\times \frac{9}{8}\times \frac{6}{5}\\\\=\frac{432}{120} = \frac{18}{5} = 3\frac{3}{5}\text{ cube feet}$

Hence, the volume of carton is $3\frac{3}{5}\text{ cube feet}$.

Answer 2

You know that volume is equal to length times width time height. You also know that the length of the carton is 2 2/3 feet, the width is 1 1/8 feet, and the height is 1 1/5 feet. 
And to find the volume, you have to multiply the length, width, and height of the carton all together, and you will get 1 1/5 as your answer.
So, the volume of the carton is 1 1/5 cubic feet. 

I hope this helps :)