2x+6=45
2x=39
x=19.5
i hope that's helpfull......... is it?
The first term is 8, so 
Each time we want a new term, we add on 3
8+3 = 11
11+3 = 14
14+3 = 17
17+3 = 20
23+3 = 26
and so on
This recursive step of adding on 3 to the prior term is written as this:
which says "to get the nth term, add 3 to the term just before the nth term"
Based on what you posted for your answer choices, the final answer is likely choice C. However it seems some weird typo happened.
Two events are occurring:
1) Rolling a die
Sample Space = {1,2,3,4,5,6}
Total number of outcomes in sample space = 6
Favorable outcomes = Odd number
Number of Favorable outcomes = 3
Probability of getting an odd number = 3/6
2) Tossing a coin
Sample Space = {H, T}
Probability of getting a head= 1/2
The probability of getting odd number and head will be the product of two probabilities, which will be = 3/6 x 1/2 = 3/12
Thus there is 3/12 = 1/4 (0.25 or 25%) probability of getting an odd number and a head in given scenario.
So correct answer is option C
<u>Answer:</u>
The probability of getting two good coils when two coils are randomly selected if the first selection is replaced before the second is made is 0.7744
<u>Solution:</u>
Total number of coils = number of good coils + defective coils = 88 + 12 = 100
p(getting two good coils for two selection) = p( getting 2 good coils for first selection )
p(getting 2 good coils for second selection)
p(first selection) = p(second selection) = 
Hence, p(getting 2 good coil for two selection) = 