Assuming that your question is (x-1)(x+2) = [5(x-1)]/x-1
On the right side, the x-1's will cancel out, leaving you with (x-1)(x+2) = 5
expand the left side, giving you x^2 + x -2 = 5
which goes to x^2 +x -7 = 0
the possible values for x are 2.93 and -3.93. I don't think this was your question, so I'll do the other possible question that you might have been asking.
(x-1)(x+2) = 5(x-1)
divide by x-1 on both sides, leaving you with x+2=5
x+2=5
x=5-3
x=3
Consider the following expanded powers of (a + b)n, where a + b is any binomial and n is a whole number. Look for patterns.
Each expansion is a polynomial. There are some patterns to be noted.
1. There is one more term than the power of the exponent, n. That is, there are terms in the expansion of (a + b)n.
2. In each term, the sum of the exponents is n, the power to which the binomial is raised.
3. The exponents of a start with n, the power of the binomial, and decrease to 0. The last term has no factor of a. The first term has no factor of b, so powers of b start with 0 and increase to n.
4. The coefficients start at 1 and increase through certain values about "half"-way and then decrease through these same values back to 1.
Answer:
-19-28i
Step-by-step explanation:
Simplify and write the answer in standard form, a+bi.
We can factor <span>4x^2-25 into (2x +5) * (2x -5) and
dividing by (2x -5)
yields (2x +5)
That neatened up pretty nicely.</span>
X^2+12x-28
(x-2)(x+14)
Solve for x
x-2=0
x=2
x+14=0
x=-14
