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Maru [420]
2 years ago
6

The quadratic function f(x) has real coefficients. Given that f(3 - 2i) = 0, what must be the

Mathematics
1 answer:
pishuonlain [190]2 years ago
4 0

Answer:

Option (C)

Step-by-step explanation:

Conjugate root theorem:

If (a - bi) is a root of a polynomial with real coefficients, then (a + bi) will be the other root.

By this theorem, if (3 - 2i) is one root of the quadratic function 'f', other root will be (3 + 2i).

Therefore, x = (3 + 2i) will be the other root.

Option (C) will be the answer.

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Answer:

The vertex is (6, -4)

Step-by-step explanation:

f(x) =(х – 8)(х – 4)

First find the zeros

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0 = x-8      0 =x-4

x=8          x=4

The zeros are x=8 and x=4

The vertex is 1/2 way between the zeros

(8+4)/2 = 12/2 =6

To find the y value, substitute 6 into the function

f(6) = (6-8) (6-4)

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The vertex is (6, -4)

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