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andrew-mc [135]
3 years ago
10

NEED HELP NOWW!!! Andre is in charge of cooking broccoli and zucchini for a large group. He has to spend all $17 he has and can

carry 10 pounds of veggies. Zucchini costs $1.50 per pound and broccoli costs $2 per pound. One graph shows combinations of zucchini and broccoli that weigh 10 pounds and the older shows combinations of zucchini and broccoli that cost $17
a. Name one combination of veggies that weighs 10 pounds but does not cost $17.

b. Name one combination of veggies that costs $17 but does not weigh 10 pounds.

c. How many pounds each of zucchini and broccoli can Andre get so that he spends all $17 and gets 10 pounds of veggies?

NO RANDOM ANSWERS OR I WILL REPORT YOU

Mathematics
2 answers:
Nookie1986 [14]3 years ago
7 0

Answer:

a. 9 pounds of broccoli and 1 pound of zucchini

b. 7lbs broccoli and 2 lbs of zucchini

c. 6lbs zucchini and 4lbs broccoli.

Step-by-step explanation:

a. well just come up with 2 numbers that equal up to 10 so yea.

b. 7lbs broccoli 2 lbs of zucchini - this is 9 lbs of veggies but it costs 17 dollars because (7*2)+(2*1.50)=17

14+3=17 (the 7 and 2 is the amount of pounds of veggies and the 2 and 1.50 are the prices)

c. it would be 6 lbs of zucchini and 4 lbs of broccoli because 6+4=10 and (6*1.50)+(4*2)=17

Valentin [98]3 years ago
3 0
A) $1.50 X 8 = $12.00
$2 X 2 = $4.00
12 + 4 = $16
8 +2 = 10 pounds
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Paladinen [302]
Let's start by writing a system of linear equations:
c -> cookies 
cb -> candy bars
(You can use any abbreviations to your preference)

Abby:
4 cookies 
3 candy bars
$10.25 per bag
The equation would be:
4c+ 3cb = $10.25

Marissa:
2 cookies
7 candy bars
$14.75 per bag
The equation would be:
2c + 7cb = $14.75

So our linear equation system would be:
<span>4c+ 3cb = $10.25
</span><span>2c + 7cb = $14.75

I would try to get rid of one variable so I can solve for the other variable. In this case, it is easier to get rid of c since I can multiply the second equations by 2. Then it would subtract the two equations.

(2c + 7cb = $14.75) 2 = 4c + 14 cb = $29.50

      4c + 3cb = $10.25
   -  4c+14 cb = $29.50                    (4c would get canceled.)
---------------------------------
             -11 cb = - $19.25                (Divide by -11 to solve for cb)
</span>             ---------   -------------
              -11           -11
            
             cb = $1.75

Now we know cb (candy bar) cost, we would substitute this value into cb into one of the equations. It doesn't matter which equation you put it in. I will substitute it in the first equations. 

  4c + 3 (1.75) = $10.25
  4c + 5.25 = $10.25                       (Multiply 3 by 1.75)
       -5.25       -5.25                         (Subtract 5.25 on both sides)
             4c = 5                                 (Divide by 4 on both sides to get c)
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Check the work:
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2(1.25) + 7(1.75)
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Total cost:
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candy bars = $ 1.75

Hope this helps! :)

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4 years ago
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Yakvenalex [24]

Answer:

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Step-by-step explanation:

Question 11

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(a) Rename g(x) as y  

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The graphs of inverse functions are reflections of each other across the line y = x.

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(c) Switch x and y  

y  = x + 2

(e) Rename y as the inverse function  

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(f) Compare with your function

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