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blondinia [14]
3 years ago
11

Expand the binomial (2x+y^2)^5

Mathematics
1 answer:
ra1l [238]3 years ago
6 0

Answer:

32x+y^10

Step-by-step explanation:

2^5 = 32

y^2*5 = y^10

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The solution to this system of equations lies between the x-values -2 and -1.5. At which x-value are the two equations approxima
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Read 2 more answers
C+ax=dx<br><br><br>this one has all variables and no numbers
sergeinik [125]
That's OK, but you have not said which variable you want to solve it for.

<u>To solve for 'x':</u>
                                           <span>c + ax = dx

Subtract c from each side:    ax = dx - c

Subtract  dx  from each side:   ax - dx = -c

Factor the left side:                 x (a - d) = -c

Divide each side by (a - d) :      x = -c / (a - d)  or  <u>x = c / (d - a)</u> .

</span><span><u>To solve for 'c': </u>
</span><span>                                   c + ax = dx

Subtract  ax  from each side and factor:   <u>c  = x (d - a) </u>

</span><u>To solve for 'd': </u>
                                      <span>c + ax = dx

Divide each side by 'x':     d = c/x + a .

<u>To solve for 'a':</u>
</span><span><span>                                           c + ax = dx</span>

Subtract 'c' from each side:    ax = dx - c

Divide each side by 'x':          <u>a = d - c/x </u>.
.</span>
6 0
3 years ago
The output of an economic system​ Q, subject to two​ inputs, such as labor L and capital​ K, is often modeled by the​ Cobb-Dougl
Anna35 [415]

Answer:

Step-by-step explanation:

Given

Economic system Q is given by

Q=cL^aK^b

also a+b=1

if Q=12,200

a=\frac{1}{6}

b=\frac{5}{6}

c=42

substitute these values

12,200=42\times (L)^{\frac{1}{6}}K^{\frac{5}{6}}

(L)^{\frac{1}{6}}K^{\frac{5}{6}}=\frac{12,200}{42}

K^{\frac{5}{6}}=\frac{12,200}{42(L)^{\frac{1}{6}}}

K=(\frac{12,200}{42})^{\frac{6}{5}}\times \frac{1}{L^{5}}

differentiate w.r.t to L to get \frac{dK}{dL}

\frac{dK}{dL}=(\frac{12,200}{42})^{\frac{6}{5}}\times (-5)\times L^{-6}

\frac{dK}{dL}=-5(\frac{12,200}{42})^{\frac{6}{5}}\times \frac{1}{L^6}

\frac{dK}{dL}=-\frac{4515.466}{L^6}

6 0
3 years ago
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