I always found it easiest to draw out the picture
Answer:
20 yd^2
Step-by-step explanation:
Your work is partially correct.
Assuming that the sides marked 8 yds and 2 yds are parallel, then the area of the trapezoid is
A = ( 8 yds + 2 yds)
------------------------ * 4 = 20 yd^2
2
Answer:
brhnrnr e euebe ehe we je euebe ejeje
Answer:
D
Step-by-step explanation:
Any other product in Quadrant IV will be negative also, so Quadrant IV is part of my answer. The points (x, y), with xy < 0, lie in Quadrants II and IV.
Step 1. Solve both inequalities for

:




Step 2. To check a point in the solution of the given system of inequalities, look for the intercepts of the lines

and

:

(1)

(2)
Replace (1) in (2):

Solve for

:


(3)
Replace (3) in (1):



We can conclude that the point (-2,3) is in the solution of the system if <span>
inequalities</span>
; also any point inside the dark shaded area of the graph of the system of inequalities is also a solution of the system.