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mars1129 [50]
3 years ago
7

Answer asap thank you!??!!??!

Mathematics
1 answer:
Semenov [28]3 years ago
7 0
The answer to the problem is A
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Show work please help
Snezhnost [94]

Answer:

20 yd^2

Step-by-step explanation:

Your work is partially correct.

Assuming that the sides marked 8 yds and 2 yds are parallel, then the area of the trapezoid is

A =    ( 8 yds + 2 yds)

        ------------------------ * 4  =  20 yd^2

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Five increased by the product of a number and 9 is greater than -27<br> As an inequality
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3 years ago
Help? Please. I really need help
tia_tia [17]

Answer:

D

Step-by-step explanation:

Any other product in Quadrant IV will be negative also, so Quadrant IV is part of my answer. The points (x, y), with xy < 0, lie in Quadrants II and IV.

3 0
3 years ago
Which point is in the solution set of the given system of inequalities 3x+y&gt;-3,x+2y&lt;4
Dima020 [189]
Step 1. Solve both inequalities for y:
3x+y\ \textgreater \ -3
y\ \textgreater \ -3x-3

x+2y\ \textless \ 4
2y\ \textless \ -x+4
y\ \textless \ - \frac{1}{2} x+2

Step 2. To check a point in the solution of the given system of inequalities, look for the intercepts of the lines -3x-3 and - \frac{1}{2} x+2:

y=-3x-3 (1)
y=- \frac{1}{2} x+2 (2)

Replace (1) in (2):
-3x-3=- \frac{1}{2} x+2
Solve for x:
\frac{5}{2} x=-5
x=-2 (3)

Replace (3) in (1):
y=-3x-3
y=-3(-2)-3
y=6-3
y=3

We can conclude that the point (-2,3) is in the solution of the system if <span>inequalities</span>; also any point inside the dark shaded area of the graph of the system of inequalities is also a solution of the system.

4 0
3 years ago
Read 2 more answers
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