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likoan [24]
3 years ago
13

Please help me graph Y=1.5x Will mark brainliest!!

Mathematics
1 answer:
Igoryamba3 years ago
5 0
Thank you! The line should pass through points (2,3), (4,6), (6,9), (8,12)
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What is 3a squared add 7 a
vfiekz [6]
The answer is:  " 9a² + 7a " .
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Note:    (3a)² + 7a = (3a)*(3a) + 7a = 9a² + 7a .
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3 0
3 years ago
Jamie will plot ( 9, 5 ) on a coordinate plane. She knows the last step is to put a point where to lines intersect. Which two st
ollegr [7]

Answer:

Step-by-step explanation:

54

I think

5 0
3 years ago
14 is the same as ?i need help
Basile [38]
Same as 7*2=14 explain more what u need
4 0
4 years ago
Given the equation 5x − 4 = –2(3x + 2), solve for the variable. Explain each step and justify your process.
blagie [28]
A.
5x-4=-2(3x+2) \ \ \ \ \ \ \ \ \ |\hbox{expand the bracket} \\
5x-4=-2 \times 3x-2 \times 2 \\
5x-4=-6x-4 \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{add 6x to both sides} \\
11x-4=-4 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{add 4 to both sides} \\
11x=0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{divide both sides by 11} \\
x=0

B.
3(2x-4)=5x-1 \\
6x-12=5x-1 \\
\boxed{11x-12=-1} \Leftarrow \hbox{the first mistake} \\
11x=11 \\
\boxed{x=11} \Leftarrow \hbox{the second mistake}

Megan's solution isn't correct.
The first mistake: she subtracted 5x from the right-hand side of the equation, but added 5x to the left-hand side.
The second mistake: she divided the right-hand side of the equation by 11, but didn't divide the left-hand side.

The correct solution:
3(2x-4)=5x-1 \ \ \ \ \ \ \ \ \ \ \ |\hbox{expand the bracket} \\
3 \times 2x+3 \times (-4)=5x-1 \\ 6x-12=5x-1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{subtract 5x from both sides} \\
x-12=-1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  |\hbox{add 12 to both sides} \\
x=11
3 0
3 years ago
F(3)= 5x^2 - 4x + 9<br> evaluate this quadratic function
Neporo4naja [7]

Answer:

f(3) = 38

Step-by-step explanation:

Given the quadratic function

f\left(x\right)=\:5x^2\:-\:4x\:+\:9

Evaluating the quadratic function

f\left(x\right)=\:5x^2\:-\:4x\:+\:9

substitute x = 3

f\left(3\right)=\:5\left(3\right)^2\:-\:4\left(4\right)\:+\:9

f(3) = 45-16+9

f(3) = 38

Therefore,

  • f(3) = 38
6 0
3 years ago
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