For there to be 1 car, we consider two possible outcomes:
The first door opened has a car or the second door opened has a car.
P(1 car) = 2/6 x 4/5 + 4/6 x 2/5
P(1 car) = 8/15
For there to be no car in either door
P(no car) = 4/6 x 3/5
P(no car) = 2/5
Probability of at least one car is the sum of the probability of one car and probability of two cars:
P(2 cars) = 2/6 x 1/5
= 1/15
P(1 car) + P(2 cars) = 8/15 + 1/15
= 3/5
1. It must be divisible by 2 and 3. It IS divisible by 2. it IS divisible by 3. No remainder.
2. Add the digits and see if the sum is divisible by 3. Apply this rule to both numbers. 3 is not a common factor.
3a. 639
3b. 1035
3c. 179
Answer:
The answer is 030
Step-by-step explanation:
I am unable to transmit my working but don't forget to write the bearing as 030 not 30
hello there
the answer is ..... down below
I did the math for ya
hope this helps
thank you
best regards Queen Z
<h2>
Explanation:</h2>
Hello! Remember you have to write complete questions in order to get good and exact answers. Here I'll assume the graphed function comes from:

So this is the equation of a parabola that opens upward and whose vertex lies on the point:

The graph of this function is shown below. Which is true regarding the graphed function f(x)?
- It is true that the domain is the set of all real numbers because this is a polynomial function.
- It is true that the range is the set of all real numbers such that y ≥ 5
- It is true that this parabola opens upward
- It is true that it doesn't cut the x-axis