Question

(please help!!!!!) Factor the polynomial b³-49b

Answer 1

Answer:

$b(b+7)(b-7)$

Step-by-step explanation:

Start by factoring a $b$ out:

$b(b^2-49b)$

For the term $b^2-49b$, we're looking for two numbers that add up to 0 and multiply to be -49:

$7+(-7)=0,\\7\cdot -7=-49$

Two numbers: $7\text{ and }-7$

Therefore, we have:

$\boxed{b(b+7)(b-7)\checkmark}$