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umka2103 [35]
3 years ago
6

Can any one do B and B please help me I need help me please thank you

Mathematics
1 answer:
MissTica3 years ago
3 0

Answer:

see below

Step-by-step explanation:

1 B    Answer :

7\times7\times7\times7\times7/7\times7\times7\times7=7    or    7^{2+3}/7^{4} =7^{5-4} =7^{1} =7

2 B    Answer :

k^{4\times2} \times k^{5} =k^{8+5} =k^{13}

3B    Answer :

5a-15-a/1=5a-a-15=4a-15

Hope that help

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The length of a rectangle field is represented by the expression 14 X minus 3X squared +2 Y. The width of the field is represent
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Answer:

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Step-by-step explanation:

Hi there!

Length of the field: 14x-3x^2+2y units

Width of the field: 5x-7x^2+7y units

To find how much greater the length of the field is than the width, subtract the width from the length:

14x-3x^2+2y-(5x-7x^2+7y)

Open up the parentheses

= 14x-3x^2+2y-5x+7x^2-7y

Combine like terms

= 14x-5x-3x^2+7x^2+2y-7y\\= 9x+4x^2-5y

Therefore, the length is 9x+4x^2-5y units greater than the width.

I hope this helps!

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2 years ago
Please read the attachment below :)
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Answer:

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