Answer:
21square feet
Step-by-step explanation:
Count the whole squares first.
if each square is one square foot then 18 whole squares will be 18×1= 18 square feet
add halves (aproximate halves) together. (3 in total)
Therefore A= 18 +3
= 21 square feet
Answer:
Step-by-step explanation:
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<em>hope this helps....</em>
Line. A line would have a length but has no width
Answer:
Class Boundary = 1 between the sixth and seventh classes.
Step-by-step explanation:
Lengths (mm) Frequency
1. 140 - 143 1
2. 144 - 147 16
3. 148 - 151 71
4. 152 - 155 108
5. 156 - 159 83
6. 160 - 163 18
7. 164 - 167 3
The class boundary between two classes is the numerical value between the starting value of the higher class, which is 164 for the 7th class in this case, and the ending value of the class of the lower class, which is 163 for the 6th class in this case.
Therefore the class boundary between the sixth and seventh classes
= 164 - 163 = 1
Therefore Class Boundary = 1.
It can be seen that class boundary for the frequency distribution is 1.
If we take the difference between the lower limits of one class and the lower limit of the next class then we will get the class width value.
Therefore, Class width,
w = lower limit of second class - lower limit of first class
= 144 - 140
= 4
Answer:
Step-by-step explanation:
The formula for determining simple interest is expressed as
I = PRT/100
Where
P represents the principal or initial amount invested.
R represents the interest rate.
T represents duration of the investment in years
From the information given,
P = $750
R = 5%
T = y years
I = the total return of Bond 1 - principal
I = 1000 - 750 = $250
Therefore,
250 = (750 × 5 × y)/100
250 = 37.5y
y = 250/37.5
y = 6.7 years
