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myrzilka [38]
3 years ago
8

Please help what are the slope and the y intercept of the linear function that is represented by the table?

Mathematics
1 answer:
miv72 [106K]3 years ago
4 0

Answer:

The slope is -2, the y-intercept is 12

Step-by-step explanation:

slope (m) = \frac{y_2 - y_1}{x_2 - x_1}

Chose any two coordinates pair. Let's make use of:

(0, 12) = (x_1, y_1)

(3, 6) = (x_2, y_2)

Thus,

slope (m) = \frac{6 - 12}{3 - 0}

slope (m) = \frac{-6}{3}

slope (m) = -2

Using the slope-intercept equation, find the y-intercept, b, as follows:

y = mx + b

Use any coordinate pair as x and y, then solve for b.

Let's use (3, 6)

6 = (-2)(3) + b

6 = -6 + b

Add 6 to both sides

6 + 6 = - 6 + b + 6

12 = b

The slope (m) of the linear function that is represented by the table is -2, while the y-intercept (b), is 12.

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We have to find the width W.

As the area is equal to the product of the length and the width, we can write this equation and solve for W as:

\begin{gathered} A=180 \\ L\cdot W=180 \\ (W+3)\cdot W=180 \\ W^2+3W=180 \\ W^2+3W-180=0 \end{gathered}

We have a quadratic equation. The roots of this equation will be the mathematical solutions.

We can find the roots using the quadratic formula:

\begin{gathered} W=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ W=\frac{-3\pm\sqrt[]{3^2-4\cdot1\cdot(-180)}}{2\cdot1} \\ W=\frac{-3\pm\sqrt[]{9+720}}{2} \\ W=\frac{-3\pm\sqrt[]{729}}{2} \\ W=\frac{-3\pm27}{2} \\ W_1=\frac{-3-27}{2}=-\frac{30}{2}=-15 \\ W_2=\frac{-3+27}{2}=\frac{24}{2}=12 \end{gathered}

The solutions are W = -15 and W = 12.

The first one is not valid, as W has to be greater than 0.

Then, the solution to our problem is W = 12 in.

Answer: the width is W = 12 inches.

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given : AD is ⊥to AB and DC, BC is ⊥ to AB and DC, angle EDC ≅ angle ECD, AD ≅ BC. prove: triangle ADE ≅ triangle BCE
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Answer:

Hence proved triangle ADE ≅ triangle BCE by Side Angle Side congruent property.

Step-by-step explanation:

Given:

AD ⊥ AB \& CD

BC ⊥ AB \& CD

AD = BC

∴ ∠ A = ∠ B = ∠ C = ∠ D =90°

∠ EDC = ∠ ECD

Solution

∠ C = ∠ BCE + ∠ ECD⇒ equation 1

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∠ C = ∠ D (given)

Substituting equation 1 and 2 in above equation we get

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