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hoa [83]
3 years ago
13

A hairstylist schedules 1/4 hour to trim a customer’s hair and 1/6 hour to style the customer’s hair. The hairstylist plans to w

ork 2 1/3 hours each day for 5 days each week. How many appointments can the hairstylist schedule each week if each customer must be trimmed and styled
Mathematics
1 answer:
Stella [2.4K]3 years ago
3 0

28 appointments can be scheduled each week if each customer must be trimmed and styled

<em><u>Solution:</u></em>

From given,

Time\ to\ trim\ hair = \frac{1}{4}\ hour

Time\ to\ style\ hair = \frac{1}{6}\ hour

<em><u>Therefore, total time taken for each customer hair to be trimmed and styled is:</u></em>

Total\ time = \frac{1}{4} + \frac{1}{6} = \frac{6+4}{24} = \frac{10}{24}\ hours\\\\Convert\ to\ minutes\\\\1\ hour = 60\ minutes\\\\Therefore\\\\\frac{10}{24}\ hour = \frac{10}{24} \times 60\ minutes = 25\ minutes

Thus, each customer trim and style = 25 minutes

Given that,

The hairstylist plans to work 2 1/3 hours each day for 5 days each week

Then, for 5 days, the hairstyist will work for:

Total\ working\ time\ of\ hairstylist = 2\frac{1}{3} \times 5\ hours\\\\\rightarrow \frac{7}{3} \times 5\ hour\\\\Convert\ to\ minutes\\\\\rightarrow \frac{7}{3} \times 5 \times 60\ minutes = 700\ minutes

Thus hairstylist will work for 700 minutes each week

<em><u>Total number of appointments:</u></em>

Total number of appointments for each week is found by dividing the working time of hair stylist for each week divided by time spent for each customer for trim and styled

Number\ of\ appointment = \frac{700}{25} = 28

Thus 28 appointments can be made

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Segment XY bisects angle WXZ and angle mZXY = 37 degrees. Find angle mWXY and angle mZXW
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A 1500 kg weather rocket accelerates upward at 10 m/s2 . It explodes 2.0 s after liftoff and breaks into two fragments, one twic
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6 0
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