PLEASE HELP!!!!!! A linear function has a y-intercept of -12 and a slope of 3/2. What is the equation of the line?
2 answers:
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The equation that runs through the location (4,-6) has the slope-intercept form, .
A line's equation written in the slope-intercept form:
y=mx+b
where m= slope & b= y-intercept
The slope of two parallel lines is equal.
Currently, we know the line's equation:
here, slope, m=
A line equation is created by adding the slope's value and the point's coordinates (4, -6):
⇒ -6=-3 +b [adding 3 to both sides]
⇒-3=b
⇒b= -3
Hence the solution is .
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Answer:
a) (8,8,-6)
b) 4x+4y+3z = -3
Step-by-step explanation:
a)
The surface is given by the equation
f(x,y,z) = 0 where
The gradient of this function is the vector
If we evaluate it in the point P = (-2,2,1) we obtain the point
(8,8,-6)
b)
The vectors with their tails at P are of the form
(-2,2,1)-(x,y,z) = (-2-x, 2-y, 1-z)
as they must be orthogonal to the gradient, they must be orthogonal to the vector (8,8,6) so their inner product is 0
and the equation of the desired plane is
4x+4y+3z = -3