Please anything helps

Mathematics

1 answer:

lisov135 [29]3 years ago

3 0

Answer:

D- Neither graph is a funvtion.

Step-by-step explanation:

A function can only have one input to one output. These have more than one output for each input. You can also do the vertical line test, if it touches more than two points at the same time while going horizontally across, it is not a function.

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Solve the system of equations<br> y=-3/2x+9 <br> 2x+2y=16

ozzi

Answer:

x=2 and y=6

Step-by-step explanation:

5 0

3 years ago

Which polynomial is factored completely? A.(4x+4) (x+1) B. 3n4 - 15n3 + 12n2 C. 121x2 + 36y D. 2x (x2-4)

morpeh [17]

B. 3n^4 - 15n^3 + 12n^2

3 0

3 years ago

Aplumber charges a $75 flat fee for jobs lasting up to an hour and $30 for each hour of labor after the first hour. Which

tamaranim1 [39]

<h3><u>Answer</u>:- </h3>

$\longrightarrow \sf 75+ 30(h-1)$

<h3><u>Solution:-</u></h3>

<u>Given </u><u>that </u><u>:</u><u>-</u>

job last for h hours
Cost of job lasting more than 1 hour = $30
Cost for the first hour = $75

$\leadsto$ Remaining hours for which the job will last after first hour= (h-1)

<u>Therefore</u>,

Cost for subsequent hours = 30×(h-1)

= 30(h-1)

Total Cost for job = Cost for 1st hour + Cost for subsequent hours

$\quad\quad\quad\quad\quad\quad\quad\quad\boxed{\sf{= 75+30(h-1)}}$

7 0

2 years ago

Which are the solutions of x^2 = –11x + 4?

strojnjashka [21]

This is a quadratic equation, i.e. an equation involving a polynomial of degree 2. To solve them, you must rearrange them first, so that all terms are on the same side, so we get

$x^2 + 11x - 4 = 0$

i.e. now we're looking for the roots of the polynomial. To find them, we can use the following formula:

$x_{1,2} = \frac{-b\pm\sqrt{b^2-4ac}}{2}$

where $x_{1,2}$ is a compact way to indicate both solutions $x_1$ and $x_2$ , while $a,b,c$ are the coefficients of the quadratic equation, i.e. we consider the polynomial $ax^2+bx+c$ .

So, in your case, we have $a=1,\ \ b=11,\ \ c=-4$

Plug those values into the formula to get

$x_{1,2} = \frac{-11\pm\sqrt{121+16}}{2} = \frac{-11\pm\sqrt{137}}{2}$

So, the two solutions are

$x_1 = \frac{-11+\sqrt{137}}{2}$

$x_2 = \frac{-11-\sqrt{137}}{2}$