Question

Diamonds have a density of 3.5 LaTeX: \frac{g}{cm^3}g c m 3. How big is a diamond that has a mass of 0.10 g?

Answer 1

For this case we have that by definition, the density is given by:

$d = \frac {M} {V}$

Where:

M: It is the mass of the diamond

V: It is the volume of the diamond

According to the data of the statement we have:

$d = 3.5 \frac {g} {cm ^ 3}\\M = 0.10 \ g$

So the volume is:

$V = \frac {M} {d}\\V = \frac {0.10 \ g} {3.5 \frac {g} {cm ^ 3}}\\V = 0.02857\\V = 0.03 \ cm^3$

Thus, the volume of the diamond is approximately $0.03 \ cm ^ 3$

Answer:

$0.03 \ cm ^ 3$