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dmitriy555 [2]
2 years ago
14

A total surface area is _ square inches

Mathematics
1 answer:
lawyer [7]2 years ago
3 0
Answer: Don’t trust those links
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(a) The parametric equations x = f(t) and y = g(t) give the coordinates of a point (x, y) = (f(t), g(t)) for appropriate values
Gnesinka [82]

Answer:

Step-by-step explanation:

a). Given a parametric equation, we are describing a set of coordinates based on the value of t. The variable t is called the parameter.

b) we have the following equations. x=t y=t^2, so in order for us to know where the object is at t=t' we must replace t with the specific value t'. Hence, when t=0 the object is at (0,0^2) = (0,0) (the origin). When t=6, the object is at (6,6^2) = (6,36).

c). To eliminate the parameter, we replace the parameter in one equation by using the second equation. Recall that we have that x=t. Then, by replacing in the second equation, we have the following

y=t^2 = (x)^2 = x^2

where x\geq 0

5 0
3 years ago
(A) A small business ships homemade candies to anywhere in the world. Suppose a random sample of 16 orders is selected and each
Leviafan [203]

Following are the solution parts for the given question:

For question A:

\to (n) = 16

\to (\bar{X}) = 410

\to (\sigma) = 40

In the given question, we calculate 90\% of the confidence interval for the mean weight of shipped homemade candies that can be calculated as follows:

\to \bar{X} \pm t_{\frac{\alpha}{2}} \times \frac{S}{\sqrt{n}}

\to C.I= 0.90\\\\\to (\alpha) = 1 - 0.90 = 0.10\\\\ \to \frac{\alpha}{2} = \frac{0.10}{2} = 0.05\\\\ \to (df) = n-1 = 16-1 = 15\\\\

Using the t table we calculate t_{ \frac{\alpha}{2}} = 1.753  When 90\% of the confidence interval:

\to 410 \pm 1.753 \times \frac{40}{\sqrt{16}}\\\\ \to 410 \pm 17.53\\\\ \to392.47 < \mu < 427.53

So 90\% confidence interval for the mean weight of shipped homemade candies is between 392.47\ \ and\ \ 427.53.

For question B:

\to (n) = 500

\to (X) = 155

\to (p') = \frac{X}{n} = \frac{155}{500} = 0.31

Here we need to calculate 90\% confidence interval for the true proportion of all college students who own a car which can be calculated as

\to p' \pm Z_{\frac{\alpha}{2}} \times \sqrt{\frac{p'(1-p')}{n}}

\to C.I= 0.90

\to (\alpha) = 0.10

\to \frac{\alpha}{2} = 0.05

Using the Z-table we found Z_{\frac{\alpha}{2}} = 1.645

therefore 90\% the confidence interval for the genuine proportion of college students who possess a car is

\to 0.31 \pm 1.645\times \sqrt{\frac{0.31\times (1-0.31)}{500}}\\\\ \to 0.31 \pm 0.034\\\\ \to 0.276 < p < 0.344

So 90\% the confidence interval for the genuine proportion of college students who possess a car is between 0.28 \ and\ 0.34.

For question C:

  • In question A, We are  90\% certain that the weight of supplied homemade candies is between 392.47 grams and 427.53 grams.
  • In question B, We are  90\% positive that the true percentage of college students who possess a car is between 0.28 and 0.34.

Learn more about confidence intervals:  

brainly.in/question/16329412

7 0
2 years ago
Whats 100000000000000000000-1000000000000000000000000
Ghella [55]

Answer: -9.999e+23

I don't know what you're up to.

7 0
3 years ago
Help please i don’t understand and this is do today :/!!
scZoUnD [109]

Answer:

5.8

Step-by-step explanation:

Using trig function Sin

7 0
3 years ago
Read 2 more answers
5. PLEASE HELP
lana66690 [7]

Answer:

The potential energy of the ball having 2kg mass would be 392 J

Step-by-step explanation:

I am assuming the ball has a mass of 2 kg, as you have not mentioned the mass of a ball.

Considering the formula for calculating the gravitational potential energy

G.P.E\:=\:m.g.h

As

m = 2 kg

Acceleration of gravity = g = 9.8 ms^{-2}

As the ball is on the height = h = 20 meters

So,

G.P.E\:=\:(2)(9.8)(20)

G.P.E\:=392 J

Therefore, the potential energy of the ball = 392 J

Keywords: potential energy, Gravitation potential energy

Learn more potential energy from brainly.com/question/14022793

#learnwithBrainly

5 0
3 years ago
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