Answer:
Step-by-step explanation:
a). Given a parametric equation, we are describing a set of coordinates based on the value of t. The variable t is called the parameter.
b) we have the following equations. x=t y=t^2, so in order for us to know where the object is at t=t' we must replace t with the specific value t'. Hence, when t=0 the object is at (0,0^2) = (0,0) (the origin). When t=6, the object is at (6,6^2) = (6,36).
c). To eliminate the parameter, we replace the parameter in one equation by using the second equation. Recall that we have that x=t. Then, by replacing in the second equation, we have the following
where
Step-by-step explanation:
Given problem is to find nearest number,
= 8888888/2915
quotient = 3049
remainder= 1053
Now, 2915-1053 = 1862
8888888+1862 = 8890750
8888888-1053 = 8887835
Two numbers nearest to 8888888 which are exactly divisible by 2915 is 8887835 and 8890750
The scenario can be described using a piecewise function like:
f(x) = 1/x if x < c.
f(x) = x if x = c
f(x) = 1/(x + 73) if x > c.
<h3>
When the value exists but the limit does not?</h3>
Remember that the limit only exists if the limit from left and the limit from the right give the same value.
Then, we can just define a piecewise function of the form:
f(x) = 1/x if x < c.
f(x) = x if x = c
f(x) = 1/(x + 73) if x > c.
Clearly, this is not a continuous function.
Notice that:
So the limits from left and right are different, then:
Does not exist.
If you want to learn more about limits:
brainly.com/question/5313449
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