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ZanzabumX [31]
3 years ago
9

Can somebody solve this?

Mathematics
2 answers:
nirvana33 [79]3 years ago
7 0

Answer:

8 months

Step-by-step explanation:

if you can get 120 per month then 950/120 = ~8

djverab [1.8K]3 years ago
5 0

Answer:

She needs $350.

Step-by-step explanation:

120 x 5 = 600

$950 - $600 = $350

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The expression 3 x 7 - 4x8+2 is equivalent to which of the following?
Mamont248 [21]
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A certain forest covers an area of 2900 km. Suppose that each year this area decreases by 8.5%. What will the area be after 8 ye
Ann [662]

Answer:

1425 square kilometer.

Step-by-step explanation:

2900 - 8.5% = 2653.5

2653.5 - 8.5% = 2427.9525

2427.9525 - 8.5% = 2221.5765375

2221.5765375 - 8.5% = 2032.74253181

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3 years ago
Read 2 more answers
A torus is formed by rotating a circle of radius r about a line in the plane of the circle that is a distance R (> r) from th
jeyben [28]

Consider a circle with radius r centered at some point (R+r,0) on the x-axis. This circle has equation

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Revolve the region bounded by this circle across the y-axis to get a torus. Using the shell method, the volume of the resulting torus is

\displaystyle2\pi\int_R^{R+2r}2xy\,\mathrm dx

where 2y=\sqrt{r^2-(x-(R+r))^2}-(-\sqrt{r^2-(x-(R+r))^2})=2\sqrt{r^2-(x-(R+r))^2}.

So the volume is

\displaystyle4\pi\int_R^{R+2r}x\sqrt{r^2-(x-(R+r))^2}\,\mathrm dx

Substitute

x-(R+r)=r\sin t\implies\mathrm dx=r\cos t\,\mathrm dt

and the integral becomes

\displaystyle4\pi r^2\int_{-\pi/2}^{\pi/2}(R+r+r\sin t)\cos^2t\,\mathrm dt

Notice that \sin t\cos^2t is an odd function, so the integral over \left[-\frac\pi2,\frac\pi2\right] is 0. This leaves us with

\displaystyle4\pi r^2(R+r)\int_{-\pi/2}^{\pi/2}\cos^2t\,\mathrm dt

Write

\cos^2t=\dfrac{1+\cos(2t)}2

so the volume is

\displaystyle2\pi r^2(R+r)\int_{-\pi/2}^{\pi/2}(1+\cos(2t))\,\mathrm dt=\boxed{2\pi^2r^2(R+r)}

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How do i factor the expressions 4w-16?
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