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rewona [7]
2 years ago
12

Find the number that is 2/3 of the way from 3/4 to 3 5/12

Mathematics
1 answer:
IRINA_888 [86]2 years ago
3 0

Answer:

I got 2.527. And the 7 repeats I’m wasn’t sure if you wanted it in a fraction but it shouldn’t be difficult to convert if you have a calculator with that function

Step-by-step explanation:

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A soda machine takes 3 seconds to fill a 15-ounce cup. If t represents the time in seconds, which equation can you use to find h
Svet_ta [14]

Information we know:

a 15 ounce cup takes 3 second to fill

determine variables:

x=3

y=15

rate:

y/x=3/15= 0.2

fixture an equation:

y=kx

y=0.2x

plug in 40 for x:

y=0.2(40)

=8

Thus, it should take 8 seconds to fill a 40-ounce cup of soda.

8 0
3 years ago
Read 2 more answers
You know that 5^2=25. How can you use this fact to evaluate 5^4
PIT_PIT [208]

Answer:

5^4 = 625

Step-by-step explanation:

5^4 is just 25 times 25

7 0
3 years ago
What is the value of
Len [333]

n-2=10n+42\qquad\text{add 2 to both sides}\\\\n=10n+44\qquad\text{subtract 10n from both sides}\\\\-9n=44\qquad\text{divide both sides by (-9)}\\\\\boxed{n=-\dfrac{44}{9}}

8 0
3 years ago
Read 2 more answers
How many solutions y= -2x -4 and y=3x plus 3
Oksi-84 [34.3K]

Answer:

The number of solutions is one

Step-by-step explanation:

Here, we want to get the number of solutions

since the linear equations are not the same, neither do they have the same x-variable, we can have only one solution

6 0
2 years ago
Select the correct answer.
ratelena [41]

Answer:

A.x(x+12) -7(x+12)

Step-by-step explanation:

Factoring is the process of taking common terms out of an expression such that one can represent the expression as the result of smaller values. When given the following expression:

x^2 +5x - 84

First, represent the linear term as the sum of two terms such that each term shares a common factor with the other terms in the expression.

x^2 +12x - 7x - 84

Now take out the common factors,

x(x+12) -7(x+12)

Thus, the correct option is choice (A).

5 0
2 years ago
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