Where is it?
step by step:
Tienes que hallar el mínimo común múltiplo de las 3 cantidades.
18= 2×3²
24= 2³×3
36= 2²×3²
mcm(18,24,36) = 2³×3²=8×9= 72
Eso quier decir que si partieron a la misma hora se encontraran de nuevo en el punto de partida 72 minutos después de la salida.
Las vueltas que habrán realizado será el resultado de dividir 72 entre el tiempo que tardan en dar una vuelta
<span>Mayor: </span> = 4
<span>Mediano: </span> = 3
<span>Pequeño: </span> = 2
Soluciónes:
se vuelven a encontrar a los 72 min de la salida
<span>El mayor dió 4 vueltas, el mediano 3 y el pequeño 2</span>
Answer:
27.4
Step-by-step explanation:
First multiply the numerator and denominator by 10
Then write the problem in long division format
Then divide 52 by 19 and get 2
Then multiply the quotient digit (2) by the divisor 19
Then subtract 38 from 52
Then bring down the next number of the dividend
Then divide 140 by 19 to get 7
Then multiply the quotient digit (7) by the divisor 19
Then subtract 133 from 140
Then add a decimal point to the solution
Then bring down the next number of the dividend
Then divide 76 by 19 to get 4
Then multiply the quotient digit (4) by the divisor 19
Then subtract 76 from 76
The solution for long division for 52.06./1.9 is 27.4
27.4
Answer:
a) 98.01%
b) 13.53\%
c) 27.06%
Step-by-step explanation:
Since a car has 10 square feet of plastic panel, the expected value (mean) for a car to have one flaw is 10*0.02 = 0.2
If we call P(k) the probability that a car has k flaws then, as P follows a Poisson distribution with mean 0.2,
a)
In this case, we are looking for P(0)
So, the probability that a car has no flaws is 98.01%
b)
Ten cars have 100 square feet of plastic panel, so now the mean is 100*0.02 = 2 flaws every ten cars.
Now P(k) is the probability that 10 cars have k flaws and
and
And the probability that 10 cars have no flaws is 13.53%
c)
Here, we are looking for P(1) with P defined as in b)
Hence, the probability that at most one car has no flaws is 27.06%
Answer:
F = 0
Step-by-step explanation:
F(x) = 2 - 2
fx/3 = 0/x
f=0