Calculate h(1):
h(a) = 2a - 4 → h(1) = 2(1) - 4 = 2 - 4 = -2
Next calculate g(-2):
g(a) = a - 5 → g(-2) = -2 - 5 = -7
<h3>Answer: g(h(1)) = -7</h3>

![\bf \sqrt{n}< \sqrt{2n+5}\implies \stackrel{\textit{squaring both sides}}{n< 2n+5}\implies 0\leqslant 2n - n + 5 \\\\\\ 0 < n+5\implies \boxed{-5 < n} \\\\\\ \stackrel{-5\leqslant n < 2}{\boxed{-5}\rule[0.35em]{10em}{0.25pt}0\rule[0.35em]{3em}{0.25pt}2}](https://tex.z-dn.net/?f=%5Cbf%20%5Csqrt%7Bn%7D%3C%20%5Csqrt%7B2n%2B5%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bsquaring%20both%20sides%7D%7D%7Bn%3C%202n%2B5%7D%5Cimplies%200%5Cleqslant%202n%20-%20n%20%2B%205%20%5C%5C%5C%5C%5C%5C%200%20%3C%20n%2B5%5Cimplies%20%5Cboxed%7B-5%20%3C%20n%7D%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B-5%5Cleqslant%20n%20%3C%202%7D%7B%5Cboxed%7B-5%7D%5Crule%5B0.35em%5D%7B10em%7D%7B0.25pt%7D0%5Crule%5B0.35em%5D%7B3em%7D%7B0.25pt%7D2%7D)
namely, -5, -4, -3, -2, -1, 0, 1. Excluding "2" because n < 2.
Answer:
The cost of the $0.5 per cookies and $1.25 per brownie.
Option (A) is correct.
Step-by-step explanation:
Let us assume that the cost of the cookies =x
Let us assume that the cost of the brownie = y
As given
Sara is selling cookies and brownies as a fundraiser for the school band.
She charges $2.25 for two cookies and one brownie.
Than the equation becomes
2x + y = 2.25
She charges $5.75 for four cookies and three brownies.
4x + 3y = 5.75
Than two equation are
2x + y = 2.25 and 4x + 3y = 5.75
Multiply 2x + y = 2.25 by 3 and subtracted from 4x + 3y = 5.75
4x - 6x + 3y - 3y = 5.75 - 6.75
-2x = - 1
2x = 1

x = $0.5
Put in the equation 2x + y = 2.25
2 × 0.5 + y = 2.25
1 + y = 2.25
y = 2.25 - 1
y = $1.25
Therefore the cost of the $0.5 per cookies and $1.25 per brownie.
Option (A) is correct.
Answer: 1 in the 1-5 range, 4 in the 6-10 range, 1 in the 11-15 range, 0 in the 16-20 range, and 5 in the 21-25 range
Explanation: it’s a histogram, similarity a bar graph, that has its data points lie within a range of values.
Answer:
I do not know
Step-by-step explanation: