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3 years ago

What is the area of the parallelogram? 3 2

Mathematics

1 answer:

KengaRu [80]3 years ago

6 0

Answer: 6

Answer Explanation: Area=Base*Height

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I need help finding what 875 divided by 46 is ?

Luda [366]

Answer:

19.02173913043478

Step-by-step explanation:

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2 years ago

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The equation of the line f is y =4/9x+3/2.Line g is perpendicular to f. What is the slope of line g?

tangare [24]

Answer:

-9/4

Step-by-step explanation:

A perpendicular slope is on that is the negative reciprocal. current slope=4/9 and the negative recipocal is -9/4.

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2 years ago

Guys please help i’m blanking!!!<br> Select all the functions whose graphs include the point (16,4)

Gnom [1K]

D and E —> substitute the x or y of the point given into the functions to test if it is correct

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3 years ago

Please help!!! Brainliest for whoever is right! What is the sum of the rational expressions below?

fenix001 [56]

Answer:

Step-by-step explanation:

$\frac{2x + 3}{3x} + \frac{x}{ x + 1}$

Write all the numerators above the least common denominator

$\frac{(x + 1)(2x + 3) + 3 {x}^{2} }{3x(x + 1)}$

Multiply the parentheses

$\frac{2 {x}^{2} + 3x + 2x + 3 + 3 {x}^{2} }{3x(x + 1)}$

Distribute 3x through the parentheses

$\frac{2 {x}^{2} + 3x + 2x + 3 + 3 {x}^{2} }{3 {x}^{2} + 3x}$

Collect like terms $=\frac{5 {x}^{2} + 5x + 3 }{3 {x}^{2} + 3 x}$

Hope this helps...

Good luck on your assignment...

6 0

3 years ago

Find all values of x for which the series converges. (Enter your answer using interval notation.) [infinity] 9 x − 7 9 n n = 0 F

makkiz [27]

Answer:

The series converges to $\frac{1}{1-9x}$ for $\frac{-1}{9} < x < \frac{1}{9}$

Step-by-step explanation:

Given the series is $\sum_{n=0}^{\infty} 9^n x^n$

We have to find the values of x for which the series converges.

We know,

$\sum_{n=0}^{\infty} ar^{n-1}$ converges to (a) / (1-r) if r < 1

Otherwise the series will diverge.

Here, $\sum_{n=0}^{\infty} 9^n x^n = \sum_{n=0}^{\infty} (9x)^{n}$ is a geometric series with |r| = | 9x |

And it converges for |9x| < 1

Hence, the given series gets converge for $\frac{-1}{9} < x < \frac{1}{9}$

And geometric series converges to $\frac{a}{1-r}$

Here, a = 1 and r = 9x

Therefore, $\frac{a}{1-r} = \frac{1}{1-9x}$

Hence, the given series converges to $\frac{1}{1-9x}$ for $\frac{-1}{9} < x < \frac{1}{9}$

4 0

3 years ago