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leonid [27]
3 years ago
12

Loook below find the area

Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
5 0

Step-by-step explanation:

step 1. this is a trapezoid. the area A = (b1 + b2)h/2 where b1 is the bottom base and b2 is the top base (per se), and h is the height. this formula is the definition of the area of a trapezoid.

step 2. A = (b1 + b2)h/2 = (22 + 9)(5)/2

step 3. A = 31(5)/2 = 155/2 = 77.5in^2.

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Kaylis [27]

Answer:

-6/10 and -12/10 (I think)

Step-by-step explanation:

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3 years ago
How do I convert standard form to point slope
Fittoniya [83]

The point-slope form:

y-y_1=m(x-x_1)

(x_1,\ y_1) - given point

m - given slope

The standard form:

Ax+By=C


y-y_1=m(x-x_1)    <em>use distributive property</em>

y-y_1=mx-mx_1      <em>add y_1 to both sides</em>

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8 0
3 years ago
Simplify<br> 1. √28<br> 2. √72<br> 3. √2 times √10<br> Please help
Mnenie [13.5K]

Answer:

Step-by-step explanation:

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5 0
3 years ago
Suppose that prices of a certain model of a new home are normally distributed with a mean of $150,000. Use the 68-95-99.7 rule t
levacccp [35]

Answer:

68% of buyers paid between $147,700 and $152,300.

Step-by-step explanation:

We are given that prices of a certain model of a new home are normally distributed with a mean of $150,000.

Use the 68-95-99.7 rule to find the percentage of buyers who paid between $147,700 and $152,300 if the standard deviation is $2300.

<u><em>Let X = prices of a certain model of a new home</em></u>

SO, X ~ Normal(\mu=150,000 ,\sigma=2,300)

The z score probability distribution for normal distribution is given by;

                             Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean price = $150,000

            \sigma = standard deviation = $2,300

<u>Now, according to 68-95-99.7 rule;</u>

Around 68% of the values in a normal distribution lies between \mu-\sigma and \mu-\sigma.

Around 95% of the values occur between \mu-2\sigma and \mu+2\sigma .

Around 99.7% of the values occur between \mu-3\sigma and \mu+3\sigma.

So, firstly we will find the z scores for both the values given;

         Z  =  \frac{X-\mu}{\sigma}  =  \frac{147,700-150,000}{2,300}  = -1

         Z  =  \frac{X-\mu}{\sigma}  =  \frac{152,300-150,000}{2,300}  = 1

This indicates that we are in the category of between \mu-\sigma and \mu-\sigma.

SO, this represents that percentage of buyers who paid between $147,700 and $152,300 is 68%.

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3 years ago
When using substitution to solve this system of equations
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Hello, find the work out in the attached image
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