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3 years ago

What is magnet made of

Physics

1 answer:

snow_tiger [21]3 years ago

5 0

Answer:

metals like iron or nickel

Explanation:

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PLEASE HELP ASAP Explain how can a ripple tank be used to view wave pattern.

Ivan

Answer:

when you push up and down the pencil right in the middle of the water tank. it will produce ripples. If seen at the perfect angle you will observe the waves

Explanation:

7 0

3 years ago

Whats the measure of how much energy a sound wave carries, the loudness of a sound?

musickatia [10]

Decibels I believe? I’m not 100% sure

6 0

3 years ago

A spinning wheel having a mass of 20 kg and a diameter of 0.5 m is positioned to rotate about its vertical axis with a constant

AlekseyPX

Answer:

ωf = 8.8 rad/s

v = 2.2 m/s

Explanation:

We will use the third equation of motion to find the maximum angular velocity of the wheel:

$2\alpha \theta = \omega_f^2 -\omega_I^2$

where,

α = angular acceleration = 6 rad/s²

θ = angular displacemnt = 1 rev = 2π rad

ωf = max. final angular velocity = ?

ωi = initial angular velocity = 1.5 rad/s

Therefore,

$2(6\ rad/s^2)(2\pi\ rad)=\omega_f^2-(1.5\ rad/s)^2\\\omega_f^2=75.4\ rad/s^2+2.25\ rad/s^2\\\omega_f = \sqrt{77.65\ rad/s^2}$

ωf = 8.8 rad/s

Now, for linear velocity:

v = rω = (0.25 m)(8.8 rad/s)

v = 2.2 m/s

7 0

3 years ago

The densities of cardboard, aluminum, and lead are 0.6 g/cm^3, 2.7 g/cm^3, and 11.4 g/cm^3, respectively. Suppose that you are s

krek1111 [17]

Answer:

For cardboard = 29.4 g/cm²

For aluminium = 113.4 g/cm²

For lead = 193.8 g/cm²

Explanation:

Given:

Density of the cardboard, d₁ = 0.6 g/cm³

Density of the aluminium, d₂ = 2.7 g/cm³

Density of the lead, d₃ = 11.4 g/cm³

Length of the cardboard, L₁ = 49 cm

Length of the aluminium, L₂ = 42 cm

Length of the lead, L₃ = 17 cm

Now,

The absorber thickness is calculated as:

= Density × Length

therefore,

For cardboard = d₁ × L₁ = 0.6 × 49 = 29.4 g/cm²

For aluminium = d₂ × L₂ = 2.7 × 42 = 113.4 g/cm²

For lead = d₃ × L₃ = 11.4 × 17 = 193.8 g/cm²

4 0

4 years ago

The pressure of an ideal gas is doubled during a process in which the energy given up as heat by the gas equals the work done on

Nadya [2.5K]

Answer:

$V' = \frac{V}{2}$

So volume is halved

Explanation:

As we know that heat energy given to the gas is equal to the work done

so as per first law of thermodynamics we know that

$\Delta Q = W + \Delta U$

now we know that

$\Delta Q = W$

so we have

$\Delta U = 0$

so we have temperature of the gas is constant

so it is an isothermal process

so here we can say

$PV = constant$

so here we can say

$P(V) = (2P)V'$

so we have

$V' = \frac{V}{2}$

5 0

3 years ago