I believe it is c because the least dense would be on top. so x is least dense, then y, and then z
Assume that an ingot of copper has a mass of 9.1 kg or 9100 g.
The cross-sectional area of the copper wire with diameter of 6.5 mm (or 0.65 cm) is
A = (π/4)*(0.65 cm)² = 0.3318 cm²
The density of copper is given as 8.94 g/cm³.
If the length of copper wire is L cm, then
(0.3318 cm²)*(L cm)*(8.94 g/cm³) = 9100 g
L = 9100/(0.3318*8.94) = 3.0678 x 10³ cm
Note that
1 cm = 1/2.54 in = 1/2.54 in = 0.3937 in
= 0.3937/12 = 0.03281 ft
Therefore
L = (3.0678 x 10³ cm)*(0.03281 ft/cm) = 100.65 ft
Answer: 100.65 ft
Answer:
the final velocity of the two blocks is
the distance that A slides relative to B is
Explanation:
From the diagram below;
acceleration of A relative to B is : 
where
v = u + at

Making t the subject of the formula; we have:


which implies the distance that A slides relative to B.
The final velocities of the two blocks can be determined as follows:
v = u + at

Thus, the final velocity of the two blocks is
Answer:
Well it would be equal to 500N because pushing forward the ball (or whatever maybe a body) would push the canon back an even 500N backwards...
Explanation: