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Zanzabum
3 years ago
15

Jared, the operations head at Cerise Confectionery, showed gratitude to his employees by hosting an employee appreciation day. I

n this scenario, Jared used the management function of _____ to boost the morale of his employees
Business
1 answer:
Art [367]3 years ago
4 0

Answer:

Leading is the correct answer.

Explanation:

Leading is a process of influencing, directing and guiding a people of an organization to show them a direction.

Leading is the function that is carried out in the management process to motivate the employees to reach the organizational objectives.

Thus leading create a positive attitude among the people working in the organization.

You might be interested in
How do most companies pay the current liabilities incurred by day-to-day operations?.
elixir [45]

Current assets, or possessions used up within a year, are generally used to settle current liabilities.

<h3>Why do you use the term "current liabilities"?</h3>
  • Current liabilities are debts or commitments that fall due within a year or during the regular business cycle. Additionally, current obligations are paid off by using a current asset, either by generating a fresh current liability or by using cash.
  • In accounting, current liabilities are frequently interpreted as all debts owed by a company that must be paid in cash within the fiscal year or the operational cycle of that particular company, whichever is longer.
  • Current assets, or possessions used up within a year, are generally used to settle current liabilities. Accounts payable, short-term loans, dividends, and notes payable are a few examples of current liabilities, along with any outstanding income taxes.  

To learn more about Current assets refer to:

brainly.com/question/13188114

#SPJ4

6 0
1 year ago
Materials used by the Instrument Division of Ziegler Inc. are currently purchased from outside suppliers at a cost of $1,350 per
Sergio039 [100]

Answer:

(a) $33750000 (b) $11250000 (c) $22500000

Explanation:

Solution

(a) How much would Ziegler Inc. total income of operating  increase.

Now,

Units * (Cost of purchased from outside supplier - Variable cost)

Thus,

75000 * ($1350 - $900) = $33750000

(b) How much would the Instrument Division's operating income increase

Now,

The Units * (Cost of purchased from outside supplier - Transfer Price)

So,

75000 units * ($1350 - $1200) = $11250000

(C) How much would the Components Division's operating income increase?

Now,

Units * (Transfer Price - Variable cost)

75000 units * ($1200 - $900) = $22500000

3 0
3 years ago
Prices of products are often higher in a foreign country than the home country due to transportation charges, taxes, tariffs, an
Genrish500 [490]

Answer:

Option E Price Escalation

Explanation:

Price Escalation is when the government imposes additional taxes on the product which is exported to their country, this makes the product expensive and the customer as a result don't buys that product. Such type of increases in prices are known as price escalation.

7 0
3 years ago
A coin sold at auction in 2017 for $1,965,500. The coin had a face value of $5 when it was issued in 1794 and had previously bee
aksik [14]

Answer:

0.0642 or 6.42%

Explanation:

The period 't' between the year when the coin was issued, 1794, and 1971 is:

t=1971-1794 \\t=177\ years

If the coin had a value of $5 and after a period of t=177 years it was worth $305,000, the annual tax rate by which the coin appreciated is determined by:

305,000 = 5*(1+r)^{177}\\r=\sqrt[177]{61,000}-1\\r=0.0642=6.42\%

The annual rate was 0.0642 or 6.42%.

4 0
3 years ago
A metal sphere of radius 15 cm has a net charge of 3.0 $ 10#8 C. (a) What is the electric field at the sphere’s surface? (b) If
denis-greek [22]

Answer:

E = 1.20 × 10^{4} N/C

V = 1800 V

x = 0.058 m

Explanation:

given data

radius = 15 cm

net charge = 3 × 10^{-8} C

electric potential decreased = 500 V

solution

we get here electric field at the sphere’s surface that is

electric field at the sphere’s surface E  =  \frac{q}{4\pi \epsilon _o R^2}   ............1

put here value

electric field at the sphere’s surface E  = \frac{3\times 10^{-8}\times 8.99\times 10^9}{ 0.15^2}    

E = 1.20 × 10^{4} N/C

and

potential on surface of sphere is

V =  \frac{q}{4\pi \epsilon _o R} ................2

V = \frac{3\times 10^{-8}\times 8.99\times 10^9}{ 0.15}  

V = 1800 V

and

now we get distance that is x

and we know here

ΔV = V(x) - V   ..............3

substitute here value

-500V = \frac{q}{4\pi \epsilon _o } \times (\frac{1}{R+x} - \frac{1}{R})

-500 V = {3\times 10^{-8}\times 8.99\times 10^9} \times (\frac{1}{0.15+x} - \frac{1}{0.15})

solve it we get x

x = 0.058 m

3 0
3 years ago
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