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2 years ago

The measures of Z1 and 22 are 30% and 45% of the sum of the angle measures of the triangle. Find

Mathematics

1 answer:

frosja888 [35]2 years ago

4 0

Answer:

45 degree or 25%

Step-by-step explanation:

sum of angles of triangle= 180 so

$180*\frac{30}{100}=54$ -----> angle 1

(note: 30% is equal to $\frac{30}{100}$ )

$180*\frac{45}{100} =81$ ------> angle 2

lets add angle 1 and 2 together

54+81=135

now lets subtract it from 180 to get the remained angle

180-135=45 and if you want it in % so you just get 100%-(30%+45%)= 25%

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1-104. Solve each equation. Give solutions in both exact and approximate forms. HomeworkHelpa. X2+3x-3=0b. 3x2-7x=12

Alex_Xolod [135]

According to the given question we have the following equations:

a. x2+3x-3=0

b. 3x2-7x=12

a. X2+3x-3=0

The first step to calculate this equation is:

Move the -3 to the other side:

So, the equation would be:

X2+3x=3

x2+3x=5x

Therefore:

5x=3

x=3/5

a. The value of x would be 3/5

b. 3x2-7x=12

First step:

Multyply 3x to 2, so:

3x*2=6x

Next we can proceed to calculate the value of x:

6x-7x=12

-x=12

x=-12

b. The value of x would be -12

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1 year ago

The coordinates of the vertices of a polygon are (-2, 1). (-3, 3), (-1, 5), (2, 4), and (2, 1). What is the perimeter of the pol

kobusy [5.1K]

Answer:

$15.2\ units$

Step-by-step explanation:

step 1

Plot the vertices of the polygon to better understand the problem

we have

$A(-2, 1). B(-3, 3), C(-1, 5), D(2, 4),E(2, 1)$

using a graphing tool

The polygon is a pentagon (the number of sides is 5)

see the attached figure

The perimeter is equal to

$P=AB+BC+CD+DE+AE$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 2

Find the distance AB

$A(-2, 1). B(-3, 3)$

substitute in the formula

$d=\sqrt{(3-1)^{2}+(-3+2)^{2}}$

$d=\sqrt{(2)^{2}+(-1)^{2}}$

$d_A_B=\sqrt{5}=2.24\ units$

step 3

Find the distance BC

$B(-3, 3), C(-1, 5)$

substitute in the formula

$d=\sqrt{(5-3)^{2}+(-1+3)^{2}}$

$d=\sqrt{(2)^{2}+(2)^{2}}$

$d_B_C=\sqrt{8}=2.83\ units$

step 4

Find the distance CD

$C(-1, 5), D(2, 4)$

substitute in the formula

$d=\sqrt{(4-5)^{2}+(2+1)^{2}}$

$d=\sqrt{(-1)^{2}+(3)^{2}}$

$d_C_D=\sqrt{10}=3.16\ units$

step 5

Find the distance DE

$D(2, 4),E(2, 1)$

substitute in the formula

$d=\sqrt{(1-4)^{2}+(2-2)^{2}}$

$d=\sqrt{(-3)^{2}+(0)^{2}}$

$d_D_E=\sqrt{9}\ units$

$d_D_E=3\ units$

step 6

Find the distance AE

$A(-2, 1).E(2, 1)$

substitute in the formula

$d=\sqrt{(1-1)^{2}+(2+2)^{2}}$

$d=\sqrt{(0)^{2}+(4)^{2}}$

$d_A_E=\sqrt{16}\ units$

$d_A_E=4\ units$

step 7

Find the perimeter

$P=AB+BC+CD+DE+AE$

substitute the values

$P=2.24+2.83+3.16+3+4=15.23\ units$

Round to the nearest tenth of a unit

$P=15.2\ units$

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