Answer:
Range values are:
{-11, 1, 4, 10, 25}
Step-by-step explanation:
Domain values are the possible x values that can be entered into the function, or the inputs. Range values are the y values, or the outputs. By inserting every value in the set into the function, we get the outputs (y values)
-15 + 4 = -11
-3+4 = 1
0 + 4 = 4
6 + 4 = 10
21 + 4 = 25
Remember to put them in order.
Answer:
No. See explanation below.
Step-by-step explanation:
No.
Since 60 × $300 = $18,000, he would be exactly at budget if he needed 60 uniforms and if each uniform cost $300, but he needs more than 60 uniforms, and each uniform costs more than $315, so the total cost is definitely more than $18,000.
He used distributive property
Answer:
a) 2.5 shots
b) 59.4 shots
c) 4.87 shots
Step-by-step explanation:
Probability of making the shot = 0.6
Probability of missing the shot = 0.4
a) The expected number of shots until the player misses is given by:
The expected number of shots until the first miss is 2.5
b) The expected number of shots made in 99 attempts is:
He is expected to make 59.4 shots
c) Let "p" be the proportion shots that the player make, the standard deviation for n = 99 shots is:
The standard deviation is 4.87 shots.
<span>Assuming that the particle is the 3rd
particle, we know that it’s location must be beyond q2; it cannot be between q1
and q2 since both fields point the similar way in the between region (due to
attraction). Choosing an arbitrary value of 1 for L, we get </span>
<span>
k q1 / d^2 = - k q2 / (d-1)^2 </span>
Rearranging to calculate for d:
<span> (d-1)^2/d^2 = -q2/q1 = 0.4 </span><span>
<span> d^2-2d+1 = 0.4d^2 </span>
0.6d^2-2d+1 = 0
d = 2.72075922005613
d = 0.612574113277207 </span>
<span>
We pick the value that is > q2 hence,</span>
d = 2.72075922005613*L
<span>d = 2.72*L</span>
