Question

A soccer ball is kicked from the ground with an initial upward velocity of 64 meters per second, and the height of the ball can be represented by the equation h = -16t^2 + 64t. After how many seconds will the ball hit the ground?

Answer 1

Answer:

t = 2 seconds

Step-by-step explanation:

Given that,

h = -16$t^{2}$ + 64 t

where h and t have their usual meaning.

To determine the number of seconds required of the ball to hit the ground, differentiate the given equation with respect to t.

0 = -32 + 64

So that,

32t = 64

t = $\frac{64}{32}$

t = 2

The ball will hit the ground in 2 seconds.