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ryzh [129]
3 years ago
13

What is the image of (2,10)(2,10) after a dilation by a scale factor of \frac{1}{2}

Mathematics
1 answer:
Lina20 [59]3 years ago
6 0

Answer:

(12/4, 8/4)

(3, 2)

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chef Diana purchase 10 1/2 pounds of beef and 5 1/2 pounds of pork to make meatloaf for her restaurant on the weekend she uses 1
natita [175]
Add the total purchase then subtract the used amount from it. U'll get 2 1/3.
3 0
4 years ago
The coordinates of point Care<br> A. (3,-1)<br> B. (1, -3)<br> C. (3,1)<br> D. (-3,1)<br> E. (-3,-1)
Mars2501 [29]
D (-3,1) hopes this helps
4 0
3 years ago
Mrs.Davis bought 6 pounds of grapes for 18 dallors at this rate how much would 72 ounces of grapes have cost
harkovskaia [24]

Answer:

Cost of 72 ounces of grapes is $13.5


Step-by-step explanation:

In order to solve his problem, we first need to get all the values in the same units.

  1 pound = 16 ounces

∴ 6 pounds= 16×6 = 96 ounces

Now by unitary method, we solve the question as follows:

price of 96 ounces of grapes = $ 18

price of 1 ounce of grapes = $ (18÷96)

∴ price of 72 ounces of grapes = $ [(18÷96)×72]

= (0.1875×72) =  $ 13.5

4 0
3 years ago
The heights in inches of orangutans Are normally distributed with a population standard deviation of 3" and an unknown populatio
CaHeK987 [17]

Answer: The 95% confidence interval is approximately (55.57, 58.43)

======================================================

Explanation:

At 95% confidence, the z critical value is about z = 1.960 which you find using a table or a calculator.

The sample size is n = 17

The sample mean is xbar = 57

The population standard deviation is sigma = 3

The lower bound of the confidence interval is

L = xbar - z*sigma/sqrt(n)

L = 57 - 1.960*3/sqrt(17)

L = 55.5738905247863

L = 55.57

The upper bound is

U = xbar + z*sigma/sqrt(n)

U = 57 + 1.960*3/sqrt(17)

U = 58.4261094752137

U = 58.43

Therefore the confidence interval (L, U) turns into (55.57, 58.43) which is approximate.

7 0
3 years ago
Find radius of the sphere from the following volume
nordsb [41]
Can you send a picture by chance?
3 0
2 years ago
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