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ValentinkaMS [17]
3 years ago
14

Simplify (1/5k)^2;uiovpvuylc gjlcgj

Mathematics
1 answer:
DENIUS [597]3 years ago
3 0

Answer:

i want points lol

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A mouse traveled a total distance of StartFraction 3 Over 24 EndFraction of a mile in a maze over the past 3 hours. The mouse tr
Artemon [7]

Step-by-step explanation:

It is given that, a mouse covered a distance of 3/24 miles over a distance of 3 hours. Each hour, the mouse traveled the same distance. Distance traveled in 1 hour can be calculated by dividing 3/24 miles by 3. So,

d=\dfrac{\dfrac{3}{24}}{3}\\\\d=\dfrac{3}{24}\times \dfrac{1}{3}\\\\d=\dfrac{1}{24}\ \text{hours}

Matt calculations shows that the distance is 3/8 hours. While dividing 3/24 by 3, he doesn't take reciprocal of 3 as a result he get 9 on numerator and 24 on denominator. Simplified fraction of 9/24 is 3/8. But the correct answer should be 1/24 hours.

3 0
3 years ago
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X⁴-12x²+36 equals what
Harrizon [31]
Hello there!

From that amount of information, you can't get a numerical value for the answer.

Hope This Helps You!
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3 years ago
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Mr. yates has an $80.00 budget to purchase a $72.00 pair of sunglasses. If there is a 6% sales tax rate, then how much under bud
Alekssandra [29.7K]

Answer:

$3.68 underbudget

Step-by-step explanation:

72*6%\\72*0.06=4.32\\Tax=4.32\\72+4.32=76.32 \ Total\\80-76.32=3.68

Hope this helped!

6 0
2 years ago
Let z be a standard normal random variable. Use the calculator provided, or this table, to determine the value of c . 0.1112
Leviafan [203]
<h2>The value of c . 0.1112 is 1.22</h2>
6 0
2 years ago
a circular oil slick is expanding at a rate of 2m^2/h. Find the rate at which it's diameter is expanding when it's radius is 1.5
aleksandrvk [35]

Answer:  \frac{4\pi}{3} \text{ meter per hour}

Step-by-step explanation:

The circular oil slick is expanding at a rate of  2 m^2/h

Let A be the area of the circular oil slick,

So, the changes in  A with respect to time (t),

\frac{dA}{dt} = 2

\frac{d(\pi r^2)}{dt} = 2

2\pi r\frac{dr}{dt} = 2

\frac{dr}{dt} = \frac{1}{\pi r}  

Also, the change in diameter with respect to time(t),

\frac{d}{dt} (2 r) = 2 \frac{dr}{dt}

\frac{d}{dt} (2 r) = 2 \times \frac{1}{\pi r}

\frac{d}{dt} (2 r) = \frac{2}{\pi r}

For r = 1.5 m,

\frac{d}{dt} ( 2 r)]_{r=1.5} = \frac{2}{\pi \times 1.5}=\frac{20}{\pi \times 15}=\frac{4\pi }{3}\text{ meter per hour}




7 0
3 years ago
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