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jok3333 [9.3K]
3 years ago
7

Rhett is solving the quadratic equation 0= x2 – 2x – 3 using the quadratic formula. Which shows the correct substitution of the

values a, b, and c into the quadratic formula?

Mathematics
1 answer:
lesya692 [45]3 years ago
4 0

Answer:

The correct option is 1.

Step-by-step explanation:

If a quadratic equation is defined as

ax^2+bx+c=0

then the quadratic formula is

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

The given equation is

0=x^2-2x-3

Here, a=1, b=-2 and c=-3.

Substitute these values in the above formula.

x=\frac{-(-2)\pm \sqrt{(-2)^2-4(1)(-3)}}{2(1)}

x=\frac{2\pm \sqrt{(-2)^2-4(1)(-3)}}{2(1)}

Therefore, the correct option is 1.

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Use the given graph. Determine the period of the function.
Ivahew [28]

Answer:

3

Step-by-step explanation:

Period of a function is the period after which the function attains the same value

in the graph attached with this problem we can see that

f(0)=1

the value of x for which function f(x) attains the value 1 again is at

x=3

f(3)=1

similarly , we see

f(6)=1 , f(9)=1

Hence we see that after every increased value of x by 3 units , we attain the same value of function . hence the period of the function is 3

6 0
3 years ago
Please please help me solve
mash [69]
(2,4) is the only possible answer because it is the only one in the shaded area
5 0
3 years ago
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vodomira [7]

It's A.



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4 0
3 years ago
Textbook: Please write as an expression involving functions of Θ alone.
Setler [38]

Step-by-step explanation:

tan(Θ + 30°)

Use angle sum formula:

tan(A + B) = (tan A + tan B) / (1 − tan A tan B)

So we can write this as:

(tan Θ + tan 30°) / (1 − tan Θ tan 30°)

tan 30° = 1/√3, so:

(tan Θ + 1/√3) / (1 − 1/√3 tan Θ)

Multiply top and bottom by √3:

(√3 tan Θ + 1) / (√3 − tan Θ)

6 0
3 years ago
Melissa buys 2 1/2 pounds of salmon and 1 1/4 pounds of swordfish. She pays a total of $31.25, and the swordfish cost $.20 per p
julsineya [31]

Answer:

The combined cost of 1 pound of salmon and 1 pound of swordfish is $16.66

Step-by-step explanation:

Let us assume the cost of 1 pound salmon = $ m

So the cost of 1 pound of 1 pound swordfish cat = $ ( m - 0.20)

Now, the Amount of salmon purchased  = 2 1/2 pounds

2\frac{1}{2}  = 2 + \frac{1}{2} = 2 + 0.5 = 2.5

So, the amount of salmon purchased = 2.5 pounds

Cost of buying 2.5 pounds = 2.5 x ( 1 pound cost)

= 2.5 ( m) = $ 2.5 m  ...... (1)

Also, the Amount of swordfish purchased  = 1 1/4 pounds

1\frac{1}{4}  = 1 + \frac{1}{4} = 1 + 0.25 = 1.25

So, the amount of swordfish purchased = 1.25 pounds

Cost of buying 1.25 pounds = 1.25 x ( 1 pound cost of swordfish)

= 1.25 ( m - 0.20) = $ 1.25 m - 0.25       .... (2)

Now, the combined cost paid  = $ 31.25

⇒Cost of buying (2.5 pounds salmon  +  1.25 pounds swordfish) = $ 31.25

or, 2.5 m +   1.25 m - 0.25  = 31.35       (from (1) and (2))

or, 3.75 m = 31.60

or, m = 31.60/3.75 =  8.43

⇒ m = $8.43

So, the cost of 1 pound salmon = m = $8.43

and the cost of 1 pound swordfish = m - 0.20 = $8.43 - 0.20 = $ 8.23

Hence, the combined cost  1 pound of salmon and 1 pound of swordfish = $8.43 + $ 8.23 =  $ 16.66

6 0
3 years ago
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