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mafiozo [28]
3 years ago
10

If you see a variable by itself what number is actually there but is invisible?

Mathematics
2 answers:
Brilliant_brown [7]3 years ago
3 0
The number 1 is the answer
Flura [38]3 years ago
3 0

Answer: 1

Step-by-step explanation:

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sasho [114]
Answer is 54^2.

since there are triangles in this one, it is easier to do this. all you have to do is make boxes in and since there are angles, outside the lines. like this picture.

the orange is 1
red and dotted is 2
blue is 3
purple is 4(a regular box which should be easy to count.

all you have to do is add up all the boxes within the boundaries.
boundary 1: 12
boundary 2: 18
boundary 3: 6
boundary 4: 36

now when the boundary has a triangle in it (1, 2, & 3) divide the number you got in half or 2.
boundary 1: 6
boundary 2: 9
boundary 3: 3

the ractangle box doesn't not get divided.
boundary 1: 6
boundary 2: 9
boundary 3: 3
boundary 4: 36

add all the numbers you got now for each boundary and that would be your area squared.

6+9+3+36=54^2

so your final answer is 54^2.

i hope this helps you.

3 0
3 years ago
What is the value of x3 . y4 when x<br> 3 and y = 0?
jonny [76]

Answer:

<h2>0</h2>

Step-by-step explanation:

x^3 \times y^4\\\\x = 3\\y =0 \\\\(3)^3\times 0^4\\\\3^3\times\:0^4\\\\\mathrm{Apply\:rule}\:0^a=0\\0^4=0\\\\=3^3\times\:0\\\\\mathrm{Apply\:rule}\:0\times\:a=0\\=0

6 0
3 years ago
Read 2 more answers
Compute <br><br> I need help
nataly862011 [7]

(\sqrt{3}-\sqrt{6}+\sqrt{12}-\sqrt{24})\times \frac{\sqrt{6}}{2} \\ (\sqrt{3}-\sqrt{6}+2\sqrt{3}-\sqrt{24})\times \frac{\sqrt{6}}{2} \\ (\sqrt{3}-\sqrt{6}+2\sqrt{3}-2\sqrt{6})\times \frac{\sqrt{6}}{2} \\ ((\sqrt{3}+2\sqrt{3})+(-\sqrt{6}-2\sqrt{6}))\times \frac{\sqrt{6}}{2} \\ (3\sqrt{3}-3\sqrt{6})\times \frac{\sqrt{6}}{2} \\ \frac{(3\sqrt{3}-3\sqrt{6})\sqrt{6}}{2} \\ \frac{3(\sqrt{3}-\sqrt{6})\sqrt{6}}{2}

7 0
2 years ago
A cabin in the shape of a regular pentagonal pyramid has a slant height of 16 feet and a base edge length of 12 feet. Paint for
s2008m [1.1K]

Answer:

Step-by-step explanation:

You were so mean I needed help and you become insensetive and just typed "cool"for the points I will show you back one day

5 0
2 years ago
In a nursery class of 18 pupils, the average is 4<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%7D%20" id="TexFormula1"
Alisiya [41]

Answer:

The sum of ages of all 18 pupils in the class = 81

Step-by-step explanation:

Total number of pupil in the class =  18

Average of years in the class = 4\frac{1}{2}

Now, 4\frac{1}{2}  = 4 + \frac{1}{2}  = 4 + 0.5 = 4.5

⇒Average of sum of ages  in the class = 4.05

Let us assume the sum of ages of all students in the class = m

By the formula for AVERAGE:

\textrm{Average of n obseravtions}  = \frac{\textrm{Sum of n observations}}{\textrm{n}}

\implies 4.5 = \frac{m}{18}

or, m =  18 x 4.5 = 81

Hence, the sum of ages of all 18 pupils in the class = 81

6 0
3 years ago
Read 2 more answers
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