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Dennis_Churaev [7]
3 years ago
14

Plz help, correct answer will get brainliest (if i can, if i can't ill still rate and give thanks)

Computers and Technology
1 answer:
Elena-2011 [213]3 years ago
6 0

Answer:

E-book : online edition of a new novel .

e-zine:online issue of today’s newspaper.

Online reference: online encyclopedia

blog: online website that posts restaurants reviews

Explanation:

Are you doing edge?

Also pleaseeeeeeeeeeeeeeeeeee mark me brainliest.

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You are given an array of integers, each with an unknown number of digits. You are also told the total number of digits of all t
Vlad [161]

Answer:

Explanation:

Since all of the items in the array would be integers sorting them would not be a problem regardless of the difference in integers. O(n) time would be impossible unless the array is already sorted, otherwise, the best runtime we can hope for would be such a method like the one below with a runtime of O(n^2)

static void sortingMethod(int arr[], int n)  

   {  

       int x, y, temp;  

       boolean swapped;  

       for (x = 0; x < n - 1; x++)  

       {  

           swapped = false;  

           for (y = 0; y < n - x - 1; y++)  

           {  

               if (arr[y] > arr[y + 1])  

               {  

                   temp = arr[y];  

                   arr[y] = arr[y + 1];  

                   arr[y + 1] = temp;  

                   swapped = true;  

               }  

           }  

           if (swapped == false)  

               break;  

       }  

   }

8 0
2 years ago
Write a program in c or c++ to perform different arithmeticoperation using switch statement .the program will take two inputinte
baherus [9]

Answer:

C code :

#include<stdio.h>

int main()

{

int j;

float k,l, x;  //taking float to give the real results.

printf("Enter your two operands: ");  //entering the numbers on which      //the operation to be performed.

scanf("%f %f", &k, &l);

 

printf("\n Now enter the operation you want to do: ");

printf("1 for Addition, 2 for Subtraction, 3 for Multiplication, 4 for Division ");

scanf("%d", &j);  //j takes the input for opearation.

 

switch(j)  

{

 case 1:  

  x=k+l;

  printf("%.2f+%.2f=%.2f",k,l,x);   //we write %.2f to get the result //upto 2 decimal point.

  break;

   

 case 2:

  x=k-l;

  printf("%.2f-%.2f=%.2f",k,l,x);

  break;

 case 3:

  x=k*l;

  printf("%.2f*%.2f=%.2f",k,l,x);

  break;

 case 4:

  if(l!=0) //division is not possible if the denominator is 0.

  {

   x=k/l;

   printf("%.2f/%.2f=%.2f",k,l,x);

  }

  else  

   printf("Division result is undefined");

               default:

   printf("\n invalid operation");

}

}

Output is in image.

Explanation:

At first we take two numbers.

Then we take integers from 1 to 4 for Addition, subtraction, multiplication, division respectively.

Then accordingly the case is followed and the operation is performed.

6 0
3 years ago
Business customers pay $0.006 per gallon for the first 8000 gallons. If the usage is more than 8000 gallons, the rate will be $0
trasher [3.6K]

Answer:

#include <bits/stdc++.h>

using namespace std;

int main()

{

   // variables

   char cust_t;

   int no_gallon;

   double cost=0;

   cout<<"Enter the type of customer(B for business or R for residential):";

   // read the type of customer

   cin>>cust_t;

   // if type is business

   if(cust_t=='b'||cust_t=='B')

   {

       cout<<"please enter the number of gallons:";

       // read the number of gallons

       cin>>no_gallon;

       // if number of gallons are less or equal to 8000

       if(no_gallon<=8000)

       {

           // calculate cost

           cost=no_gallon*0.006;

           cout<<"total cost is: $"<<cost<<endl;

       }

       else

       {

           // if number of gallons is greater than 8000

           // calculate cost

           cost=(8000*0.006)+((no_gallon-8000)*0.008);

           cout<<"total cost is: $"<<cost<<endl;

           

       }

       

   }

   

   // if customer type is residential

   else if(cust_t=='r'||cust_t=='R')

        {

           

       cout<<"please enter the number of gallons:";

       // read the number of gallons

       cin>>no_gallon;

       // if number of gallons are less or equal to 8000

       if(no_gallon<=8000)

       {

           // calculate cost

           cost=no_gallon*0.007;

           cout<<"total cost is: $"<<cost<<endl;

       }

       else

       {// if number of gallons is greater than 8000

       // calculate cost

           cost=(8000*0.005)+((no_gallon-8000)*0.007);

           cout<<"total cost is: $"<<cost<<endl;      

       }        

   }

return 0;

}

Explanation:

Ask user to enter the type of customer and assign it to variable "cust_t". If the customer type is business then read the number of gallons from user and assign it to variable "no_gallon". Then calculate cost of gallons, if  gallons are less or equal to 800 then multiply it with 0.006.And if gallons are greater than 8000, cost for  first 8000 will be multiply by 0.006 and  for rest gallons multiply with 0.008.Similarly if customer type is residential then for first 8000 gallons cost will be multiply by 0.005 and for rest it will  multiply by 0.007. Then print the cost.

Output:

Enter the type of customer(B for business or R for residential):b                                                                                            

please enter the number of gallons:9000                                                                                                                      

total cost is: $56  

4 0
3 years ago
When you print ____, the presentation is printed with one or more slides on each piece of paper?
Artist 52 [7]
When you print handouts, the presentation is printed with one or more slides on each piece of paper. When you print handouts, it's best to have the presentation printed on them for those who can not view the presentation clearly to follow along with. This also serves as a great tool for people who missed the presentation to receive a handout later or for those there to take home and review. 
8 0
3 years ago
Environmental technology examples
meriva

Exhaust Gas Recirculation (EGR) for NOx control
<span>Positive Crankcase Ventilation (PCV) for HC emission control </span>
Evaporative Emissions Control(EVAP)
<span>Catalytic Converter for HC and NOx control</span>
6 0
3 years ago
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